Question

What is the equation of the following graph?

Answer 1

The graph represents a parabola which opens towards right . ANd for such parabola, the equation of the parabola is

$x=a(y-k)^2 +h$

Here the vetex, (h,k) is (1,2).And it passes through point (2,5) . So on substituting these values, we will get

$2=a(5-2)^2 +1 => 2=9a +1=>a=1/9$

So the required equation is

$x=\frac{1}{9}(y-2)^2 +1$