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4 years ago

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An AC generator has an output rms voltage of 100.0 V at a frequency of 42.0 Hz. If the generator is connected across a 45.0-mH i

nductor, find the following. (a) inductive reactance Ω (b) rms current A (c) maximum current in the circuit

1 answer:

Rus_ich [418]4 years ago

4 0

Answer:

(a) 11.8692‬ ohm

(b) 12.447 A

(c) 17.6 A

Explanation:

a) inductive reactance Z = L Ω

= L x 2π x F

= 45.0 x 10⁻³ x 2(3.14) x 42

= 11.8692‬ ohm

b) rms current

= 100 / 8.034

= 12.447 A

c) maximum current in the circuit

= I eff x rac2

= 12.447 x 1.414

= 17.6 A

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Answer with Explanation:

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A tungsten wire is 1.5m long and has a diameter of A current of flows through the wire. The resistivity of the wire is 5.6 * 10

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Complete Question:

A tungsten wire is 1.5 m long and has a diameter of 1.0 mm. A current of 60 mA flows through the wire. The resistivity of the wire is 5.6 * 10^-8 Ωm. What is the potential difference across the ends of the wire?

Answer:

Potential difference, V = 0.00642 Volts.

Explanation:

Given the following data;

Diameter = 1 mm to meters = 1/1000 = 0.001 m

Length = 1.5m

Current = 60mA = 60/1000 = 0.06 Amperes.

Resistivity = 5.6 * 10^-8 Ωm

To find the potential difference across the ends of the wire;

First of all, we would determine the cross-sectional area of the wire (circle);

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Area = 3.142 × (0.0005)²

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Next, we find the resistance of wire;

Mathematically, resistance is given by the formula;

$Resistance = P \frac {L}{A}$

Where;

P is the resistivity of the material.

L is the length of the material.

A is the cross-sectional area of the material.

Substituting into the formula, we have;

$Resistance = 5.6 * 10^{-8} \frac {1.5}{7.855 * 10^{-7}}$

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Resistance = 0.107 Ohms.

Now, we can find the potential difference using the formula;

$V = IR$

Where;

V represents voltage or potential difference measured in volts.

I represents current measured in amperes.

R represents resistance measured in ohms.

Substituting into the formula, we have;

$V = 0.06*0.107$

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