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DENIUS [597]
3 years ago
7

What are the different advantages of a) the series vs. b) the parallel circuits? The resistors could be replaced with lightbulbs

or any other household objects including switches and fuses. Can you imagine a real situation in which you would want c) a parallel circuit? Can you imagine a situation in which you would want d) a series circuit?
Physics
1 answer:
Molodets [167]3 years ago
4 0

Answer:

In parallel circuits all components have the same voltage. In series circuits all components have the same current.

Explanation:

Voltage in a circuit is akin to pressure in water, while current is akin to flow in water.

Voltage and current are related to resistance by Ohm's law:

V = R*I

Where:

V: voltage

I: current

R: resistance

In a parallel circuit all the terminals of one side of the devices are connected together. This is known as a node. Nodes have a certain voltage. Devices connected in parallel will have one node on each side, and each node will have it's own voltage. Current will flow through each component independently depending on their resistance, so it is not the same for all of them.

In a series circuit components are connected one after the other, the current that flows through one must continue and flow through the next, so they all have the same current. But since they might have different resistances they might have different voltage differences between their terminals.

Parallel connection is useful when you have devices that require a specific voltage, such as household appliances. All wall power outlets are connected in parallel.

Series connection is useful when you want to control current. When you use a LED you must be careful not to apply an overcurrent, so a series resistor is commonly used to limit the current.

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Answer: Satellite X has a greater period and a slower tangential speed than Satellite Y

Explanation:

According to Kepler’s Third Law of Planetary motion “The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.

T^{2}=\frac{4\pi^{2}}{GM}r^{3}    (1)

Where;

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So for satellite X, the orbital period T_{X} is:

T_{X}^{2}=\frac{4\pi^{2}}{GM}r_{X}^{3}    (2)

Where r_{X}=1.2(10)^{6}m

T_{X}^{2}=\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}(1.2(10)^{6}m)^{3}    (3)

T_{X}=413.712 s    (4)

For satellite Y, the orbital period T_{Y} is:

T_{Y}^{2}=\frac{4\pi^{2}}{GM}r_{Y}^{3}    (5)

Where r_{Y}=1.9(10)^{5}m

T_{Y}^{2}=\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}(1.9(10)^{5}m)^{3}    (6)

T_{Y}=26.064 s    (7)

This means T_{X}>T_{Y}

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<u>For Satellite X:</u>

V_{X}=\sqrt{\frac{GM}{r_{X}}} (8)

V_{X}=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}{1.2(10)^{6}m}}

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V_{Y}=\sqrt{\frac{GM}{r_{Y}}} (10)

V_{Y}=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}{1.9(10)^{5}m}}

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This means V_{Y}>V_{X}

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