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DENIUS [597]
4 years ago
7

What are the different advantages of a) the series vs. b) the parallel circuits? The resistors could be replaced with lightbulbs

or any other household objects including switches and fuses. Can you imagine a real situation in which you would want c) a parallel circuit? Can you imagine a situation in which you would want d) a series circuit?
Physics
1 answer:
Molodets [167]4 years ago
4 0

Answer:

In parallel circuits all components have the same voltage. In series circuits all components have the same current.

Explanation:

Voltage in a circuit is akin to pressure in water, while current is akin to flow in water.

Voltage and current are related to resistance by Ohm's law:

V = R*I

Where:

V: voltage

I: current

R: resistance

In a parallel circuit all the terminals of one side of the devices are connected together. This is known as a node. Nodes have a certain voltage. Devices connected in parallel will have one node on each side, and each node will have it's own voltage. Current will flow through each component independently depending on their resistance, so it is not the same for all of them.

In a series circuit components are connected one after the other, the current that flows through one must continue and flow through the next, so they all have the same current. But since they might have different resistances they might have different voltage differences between their terminals.

Parallel connection is useful when you have devices that require a specific voltage, such as household appliances. All wall power outlets are connected in parallel.

Series connection is useful when you want to control current. When you use a LED you must be careful not to apply an overcurrent, so a series resistor is commonly used to limit the current.

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A rocket engine uses fuel and oxidizer in a reaction that produces gas particles having a velocity of 1380 ms The desired thrust
bearhunter [10]

Answer:

a. 141.3 kg/s b. 5.49 m/s² c. i. 104228.9 N ii. 8.53 m/s² d. i. 97305.2 N ii. 9.84 m/s²

Explanation:

a. What must be the fuel/oxidizer consumption rate (in kg s1)?

The thrust T = Rv where R = mass consumption rate and v = velocity of rocket. Since T = 195000 N and v = 1380 m/s,

R = T/v = 195000 N/1380 m/s = 141.3 kg/s

b. If the initial weight of the rocket is 125000 N, what is its initial acceleration?

We also know that thrust T - W = ma since the rocket has to move against gravity. where M = mass of rocket = W/g = 125000 N/9.8m/s² = 12755.1 kg, W = weight of rocket = 125000 N, a = acceleration of rocket and T = thrust = 195000 N.

So, T - W = Ma

195000 N - 125000 N = (12755.1 kg)a

70000 N = ma

a = 70000 N/12755.1 kg = 5.49 m/s²

c. What are the weight and acceleration of the rocket at t 15.0 s after ignition?

We know that the loss in mass ΔM = mass consumption rate × time = Rt. Since R = 141.3 kg/s and t = 15 s,

ΔM = 141.3 kg/s × 15 = 2119.5 kg

The new mass is thus M = M - ΔM = 12755.1 kg - 2119.5 kg = 10635.6 kg

i.The weight after 15 seconds is thus W' = M'g = 10635.6 kg × 9.8m/s² = 104228.9 N

ii. Since T - W' = M'a. where M' is our new mass and a our new acceleration,

a = (T - W')/M'

= (195000 N - 104228.9 N)/10635.6 kg

= 90771.1 N/10635.6 kg

= 8.53 m/s²

d. What are the weight and acceleration of the rocket at 20.0 s after ignition?

We know that the loss in mass ΔM" = mass consumption rate × time = Rt. Since R = 141.3 kg/s and t = 20 s,

ΔM" = 141.3 kg/s × 20 = 2826 kg

The new mass is thus M" = M - ΔM" = 12755.1 kg - 2826 kg = 9929.1 kg

i. The weight after 20 seconds is thus W" = M"g = 9929.1 kg × 9.8m/s² = 97305.2 N

ii. Since T - W" = M"a. where M" is our new mass and a our new acceleration,

a = (T - W")/M"

= (195000 N - 97305.2 N)/9929.1 kg

= 97694.8 N/9929.1 kg

= 9.84 m/s²

4 0
3 years ago
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Ivenika [448]

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Explanation:

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3 years ago
What is the velocity of Car B after collision?
zubka84 [21]

Answer:

30m/s

Explanation:

m1v1=m2v2

12 * 10=4* v2

120/4 =v2

V2=30m/s

7 0
3 years ago
What is newton first law​
andrew11 [14]

Answer:

Newtons first law states that:

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<em>'</em><em>This</em><em> </em><em>law</em><em> </em><em>i</em><em>s</em><em> </em><em>also</em><em> </em><em>known</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>law</em><em> </em><em>of</em><em> </em><em>Inertia</em><em>.</em><em>'</em>

5 0
3 years ago
What is the correct formula for of the weight w of an object? assume that its mass is m, the magnitude of its acceleration is a,
Vsevolod [243]
Weight = Mass × Acceleration
6 0
3 years ago
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