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DENIUS [597]
4 years ago
7

What are the different advantages of a) the series vs. b) the parallel circuits? The resistors could be replaced with lightbulbs

or any other household objects including switches and fuses. Can you imagine a real situation in which you would want c) a parallel circuit? Can you imagine a situation in which you would want d) a series circuit?
Physics
1 answer:
Molodets [167]4 years ago
4 0

Answer:

In parallel circuits all components have the same voltage. In series circuits all components have the same current.

Explanation:

Voltage in a circuit is akin to pressure in water, while current is akin to flow in water.

Voltage and current are related to resistance by Ohm's law:

V = R*I

Where:

V: voltage

I: current

R: resistance

In a parallel circuit all the terminals of one side of the devices are connected together. This is known as a node. Nodes have a certain voltage. Devices connected in parallel will have one node on each side, and each node will have it's own voltage. Current will flow through each component independently depending on their resistance, so it is not the same for all of them.

In a series circuit components are connected one after the other, the current that flows through one must continue and flow through the next, so they all have the same current. But since they might have different resistances they might have different voltage differences between their terminals.

Parallel connection is useful when you have devices that require a specific voltage, such as household appliances. All wall power outlets are connected in parallel.

Series connection is useful when you want to control current. When you use a LED you must be careful not to apply an overcurrent, so a series resistor is commonly used to limit the current.

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luda_lava [24]
As the steam touches the skin, it undergoes a phase change and releases latent heat due to the phase change. As it reaches equilibrium, it releases sensible heat. We calculate as follows:

Q = latent heat + sensible Heat
Q = 2.26 kJ / g (50.0 g) + 50.0 g ( 4.18 J / g C) (37 C - 100 C) ( 1 kJ / 1000 J)
Q = 99.833 kJ
6 0
3 years ago
Read 2 more answers
1.Which of the following is evidence that the Earth is round?
PtichkaEL [24]

Answer:

1\D. Both A and C

2\A true

5 0
3 years ago
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A block of wood is 4 cm wide, 5 cm long, and 10 cm high. It weighs 100 grams. Calculate its volume. Calculate its density. Will
77julia77 [94]

Answer:

V=200cm^3\\\\\rho =0.500g/cm^3

It will float.

Explanation:

Hello.

In this case, given the width, length and height, we can compute the volume as follows:

V=W*L*H\\\\V=4cm*5cm*10cm\\\\V=200cm^3

Moreover, since the density is computed via the division of the mass by the volume:

\rho =\frac{m}{V}

We obtain:

\rho =\frac{100g}{200cm^3} \\\\\rho =0.500g/cm^3

In such a way, since the solid has a lower density than the water, we infer it will float.

Best regards.

3 0
4 years ago
A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an ang
adell [148]

Answer:

A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of 36.9 ∘ above the horizontal. The monitor's speed is a constant 2.30 cm/s.

how much work is done on the monitor by (a) friction, (b) gravity

work(friction) = 453.5J

work(gravity) = -453.5J

Explanation:

Given that,

mass = 14kg

displacement length = 5.50m

displacement angle = 36.9°

velocity = 2.30cm/s

F = ma

work(friction) = mgsinθ .displacement

                      = (14) (9.81) (5.5sin36.9°)

                       = 453.5J

work(gravity)

= the influence of gravity oppose the motion of the box and can be pushing down, on the box from and angle of (36.9° + 90°)

= 126.9°

work(gravity) = (14) (9.81) (5.5cos126.9°)

                      = -453.5J

8 0
3 years ago
A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the
mylen [45]

Answer:

Angular acceleration, is 708.07\ rad/s^2

Explanation:

Given that,

Initial speed of the drill, \omega_i=0

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, \omega_f=28940\ rev/min=3030.58\ rad/s

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

\alpha =\dfrac{\omega_f}{t}\\\\\alpha =\dfrac{3030.58\ rad/s}{4.28\ s}\\\\\alpha =708.07\ rad/s^2

So, the drill's angular acceleration is 708.07\ rad/s^2.

4 0
3 years ago
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