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avanturin [10]
3 years ago
6

A bell is rung. What best describes the density of air around the bell? The air density does not change. The air density increas

es and then returns to normal levels. The air density decreases and then returns to normal levels. The air density increases and decreases repeatedly before returning to normal.
Physics
2 answers:
dezoksy [38]3 years ago
7 0

I think the closest possible answer to this question is The air density increases and decreases repeatedly before returning to normal.Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
Yakvenalex [24]3 years ago
4 0

The correct answer to the question is : D). The air density increases and decreases repeatedly before returning to normal

EXPLANATION:

Before coming into any conclusion, first we have to understand sound wave.

A sound wave is a longitudinal wave in which the vibration of particles are parallel to the direction of wave propagation. It moves in the form of compression and rarefaction.

Compression is the high pressure region where particles are closely aggregated. Rarefaction is the region of low pressure where particles of the medium are not so close to each other just like compression.

Hence, the correct statement  will be that the air density increases and decreases repeatedly before returning to normal .

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When a truck travels in equal distances in equal intervals of time then we say that the body has got a uniform velocity. In the above example a truck is traveling at 5 miles in all the positions at A, B, and C and all in the intervals of 5 minutes each.

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7. A 1000 kg car is rolling down the street at 2.5 m/s. How fast would a 2500 kg car have to
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1 m/s

Explanation:

To solve this question we use the following formula:

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momentum of the first car = 1000 kg × 2.5 m/s

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A projectile is launched
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The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

The given parameters;

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  • initial vertical velocity, v_y =0
  • time interval 1 seconds

The components of the velocity can be horizontal or vertical velocity.

The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.

The vertical component of the velocity is calculated as;

v_y = v_0_y -gt\\\\v_y = 0 - (1\times 9.8)\\\\v_y = -9.8 \ m/s

The horizontal component of the velocity is constant since it is not affected by gravity.

The horizontal component of the velocity = 16 m/s

Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

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