Question

what is the specific heat capacity of silver metal if 55.00g of the absored 47.3 calories of heat and temperature rise 15.°c​

Answer 1

Answer:

$0.240 J/(g^{\circ}C)$

Explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by $\Delta T$ according to the equation

$Q=mC_s \Delta T$

where

$C_s$ is the specific heat capacity of the substance

In this problem, we have:

m = 55.0 g is the mass of the sample of silver

$Q = 47.3 \cdot 4.184 = 197.9 J$ is the amount of energy supplied to the sample

$\Delta T = 15^{\circ}C$ is the change in temperature of the sample

Solving the equation for $C_s$, we find the specific heat capacity of silver:

$C_s = \frac{Q}{m \Delta T}=\frac{197.9}{(55.0)(15)}=0.240 J/(g^{\circ}C)$