The fatal current is 51 mA = 0.051 Ampere.
The resistance is 2,050Ω .
Voltage = (current) x (resistance)
= (0.051 Ampere) x (2,050 Ω) = 104.6 volts .
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This is what the arithmetic says IF the information in the question
is correct.
I don't know how true this is, and I certainly don't plan to test it,
but I have read that a current as small as 15 mA through the
heart can be fatal, not 51 mA .
If 15 mA can do it, and the sweaty electrician's resistance is
really 2,050 Ω, then the fatal voltage could be as little as 31 volts !
The voltage at the wall-outlets in your house is 120 volts in the USA !
THAT's why you don't want to stick paper clips or a screwdriver into
outlets, and why you want to cover unused outlets with plastic plugs
if there are babies crawling around.
If you have a skateboard and you skate into a tree on accident the same amount of force you put onto that tree when you was on the skateboard will come back at you when you bounce back
Explanation:
The electric field of an isolated charged parallel-plate capacitor is given by :
........(1)
Where
q is the electric charge
A is the area of cross section of parallel plate
It is clear from equation (1) that the electric field of a parallel plate capacitor is directly proportional to the charge on the plate and inversely proportional to the area of cross section of a plate.
So, the correct option is (E) i.e. "none of the above".
Answer:
u = - 20 cm
m =![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
Given:
Radius of curvature, R = 10 cm
image distance, v = 4 cm
Solution:
Focal length of the convex mirror, f:
f = ![\frac{R}{2} = \frac{10}{2} = 5 cm](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7B2%7D%20%3D%20%5Cfrac%7B10%7D%7B2%7D%20%3D%205%20cm)
Using Lens' maker formula:
![\frac{1}{f} = \frac{1}{u} + \frac{1}{v}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%20%3D%20%5Cfrac%7B1%7D%7Bu%7D%20%2B%20%5Cfrac%7B1%7D%7Bv%7D)
Substitute the given values in the above formula:
![\frac{1}{5} = \frac{1}{u} + \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%20%3D%20%5Cfrac%7B1%7D%7Bu%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D)
![\frac{1}{u} = \frac{1}{5} - \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bu%7D%20%3D%20%5Cfrac%7B1%7D%7B5%7D%20-%20%5Cfrac%7B1%7D%7B4%7D)
u = - 20 cm
where
u = object distance
Now, magnification is the ratio of image distance to the object distance:
magnification, m =![\frac{|v|}{|u|}](https://tex.z-dn.net/?f=%5Cfrac%7B%7Cv%7C%7D%7B%7Cu%7C%7D)
magnification, m =![\frac{|4|}{|-20|}](https://tex.z-dn.net/?f=%5Cfrac%7B%7C4%7C%7D%7B%7C-20%7C%7D)
m =![\frac{4}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B20%7D)
m =![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
Moving a spring back and forth creates a longitudinal wave