Answer:
3.844 x 10 to the 5th power
Explanation:
Answer:
F = 2,894 N
Explanation:
For this exercise let's use Newton's second law
F = m a
The acceleration is centripetal
a = v² / r
Angular and linear variables are related.
v = w r
Let's replace
F = m w² r
The radius r and the length of the rope is related
cos is = r / L
r = L cos tea
Let's replace
F = m w² L cos θ
Let's reduce the magnitudes to the SI system
m = 101.7 g (1 kg / 1000g) = 0.1017 kg
θ = 5 rev (2π rad / rev) = 31,416 rad
w = θ / t
w = 31.416 / 5.1
w = 6.16 rad / s
F = 0.1017 6.16² 0.75 cos θ
F = 2,894 cos θ
The maximum value of F is for θ equal to zero
F = 2,894 N
An open system is a system that has external interactions.
a closed system is a physical system that does not allow certain types of transfers in our out of the system.
an isolated system obeys the conservation law that its total energy- mass stays constant.
In this case you must consider two effects: the action of the force and the effect of the weight of the object:
Answer:
4.186 m/s^2
Explanation:
First, convert km/hr to m/s:
(75 km/hr)(1000m/1km)(1hr/60min)(1min/60s) = 20.83 m/s
Then, divide 20.93 m/s by 5.0s
(20.93 m/s) / (5.0s) = 4.186 m/s^2