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fiasKO [112]
3 years ago
14

I don't get Physics, can you help me, also i'm a begginer

Physics
2 answers:
leonid [27]3 years ago
5 0

Answer:

What is the question you are having?

Explanation:

polet [3.4K]3 years ago
3 0
Where’s the question ?
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U=R•I=6•6=36 V

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What would the answer be ?
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Hope this helps :)
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3 years ago
How many nuclei decay in one half life?
Archy [21]

Answer:

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Explanation:

4 0
3 years ago
Read 2 more answers
A train starts from a station with a constant acceleration of at = 0.40 m/s2. A passenger arrives at the track time t = 6.0s aft
jok3333 [9.3K]

Answer:

4.8 m/s  

Explanation:

When she catches the train,

  1. They will have travelled the same distance.and
  2. Their speeds will be equal

The formula for the distance covered by the train  is

d = ½at² = ½ × 0.40t² = 0.20t²

The passenger starts running at a constant speed 6 s later, so her formula is

d = v(t - 6.0)

The passenger and the train will have covered the same distance when she has caught it, so

(1) 0.20t² = v(t - 6.0)

The speed of the train is

v = at = 0.40t

The speed of the passenger is v.

(2) 0.40t = v

Substitute (2) into (1)

0.20t² = 0.40t(t - 6.0) = 0.40t² - 2.4 t

Subtract 0.20t² from each side

0.20t² - 2.4t = 0

Factor the quadratic

t(0.20t - 2.4) = 0

Apply the zero-product rule

t =0     0.20t - 2.4 = 0

                   0.20t = 2.4

(3)                      t = 12

We reject t = 0 s.

Substitute (3) into (2)

0.40 × 12 = v

            v = 4.8 m/s

The slowest constant speed at which she can run and catch the train is 4.8 m/s.

A plot of distance vs time shows that she will catch the train 6 s after starting. Both she and the train will have travelled 28.8 m. Her average speed is 28.8 m/6 s = 4.8 m/s.

7 0
4 years ago
A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.
Genrish500 [490]

Answer:

Velocity= 19.05 m/s

Kinetic energy= 3.08 J

Explanation:

The corn possess potential energy. Feom law of conservation of energy, all the potential eneegy will be converted to kinetic energy, with negligible friction.

Potential energy, PE= kinetic energy, KE

Potential energy is given by mgh while kinetic energy is given by 0.5mv^{2}

Equating

mgh=0.5mv^{2}

Making v the subject of the formula then

v=\sqrt {2gh}

Substituting 9.81 m/s2 for g and 18.5 m for h then the velocity will be

v=\sqrt {2\times 9.81\times 18.5}=19.0517715711689\ m/s\\v\approx 19.05\ m/s

To get the kinetic eneegy, since PE=KE AND KE is

KE=0.5mv^{2}

Substituting v with 19.05 and m with 0.017 kg we have

0.5\times 0.017\times 19.05^{2}=3.08467125/ J\approx 3.08 J

This can also be achieved by mgh since PE=KE hence 0.17*9.81*18.5=3.085245 J and the results are slightly different due to small energy losses and rounding off of values.

7 0
3 years ago
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