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skad [1K]
2 years ago
10

Transfer of thermal or heat energy through "touch"

Physics
1 answer:
MaRussiya [10]2 years ago
4 0
It is conduction. Rhejrjrjejehrhrhvrbrgr
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A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectivel
faust18 [17]

Answer:

The time is 5.10 sec.

Explanation:

Given that,

Component of velocity are 30 m/s and 40 m/s.

We need to calculate the resultant velocity

Using formula of resultant velocity

v=\sqrt{v_{x}^2+v_{y}^2}

Put the value into the formula

v=\sqrt{(30)^2+(40)^2}

v=50\ m/s[

We need to calculate the time

Using equation of motion

v = u+gt

v = 0+gt

t=\dfrac{v}{g}

Put the value into the formula

t=\dfrac{50}{9.8}

t=5.10\ sec

Hence, The time is 5.10 sec.

7 0
2 years ago
What do you need to know to be able to determine how far a projectile travels horizontally?
Effectus [21]
As for me, there are two suitable answers for the question represented above and here is a short explanation why I consider these two to be correct : 
D. The horizontal velocity of the projectile and <span>B. The length of time before it lands 
</span>v_x = v*cos(x) [&#10;&#10;d_x = v_x(t) + ½at² -- this led me to answers! Hope everything is clear! Regards!<span>
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5 0
3 years ago
Which is an example of gaining a static charge by conduction?
lianna [129]

Answer:

shuffling shoes

Explanation:

7 0
3 years ago
a person dives off the edge of aa cliff 33m above the surface of the sea. assuming that air resistance is negligible, how long d
USPshnik [31]

Answer:

The time is t = 2.595 \  s

The speed is v = 25.43 \ m/s

Explanation:

From the question we are told that

    The height of the cliff is  h =  33 \  m

 Generally from kinematic equation we have that

       h  =  ut + \frac{1}{2} gt^2

before the jump the persons initial velocity is  u =  0 m/s

 So

        33   =  0 * t + \frac{1}{2} 9.8 * t^2

=>      t = 2.595 \  s

Generally from kinematic equation

     v= u + gt

=>  v= 0 + 9.8 * 2.595

=>  v = 25.43 \ m/s

3 0
2 years ago
Two pipes of equal length are each open at one end. Each has a fundamental frequency of 470 Hz at 310 K. In one pipe the air tem
Tresset [83]

Answer:

Given:

Fundamental frequency: 470Hz

T1:310k,T2:315k

Calculating velocity

Recall v=(331m/s)✓[T1/273k)

V=331✓(310/273)

V1=331*(1.0656)=352.72m/s

V2=331✓(315/273)=355.5m/s

Fundamental frequency=4L

F2=F1(V2/V1)

F2=470(355.5/352.72)=474.4Hz

Beat=[F2-F1]=474.4-470=4.4Hz

Explanation:

7 0
3 years ago
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