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skad [1K]
3 years ago
10

Transfer of thermal or heat energy through "touch"

Physics
1 answer:
MaRussiya [10]3 years ago
4 0
It is conduction. Rhejrjrjejehrhrhvrbrgr
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A car, starting from rest, accelerates at
Mekhanik [1.2K]
Using V= vo +at with Vo = 0 and a= 4m/sec2.
V= 0+ 4x8= 32m/s
3 0
3 years ago
Read 2 more answers
The PVT behavior of a certain gas is described by the equation of state: P(V − b) = RT where b is a constant. If in addition CV
alexdok [17]

Answer:

shown in the attachment

Explanation:

The detailed step by step and necessary mathematical application is as shown in the attachment.

6 0
4 years ago
Help with this question.....​
mariarad [96]

Answer:

g_{moon}=1.67 [m/s^{2} ]

Explanation:

The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.

w =m*g\\

where:

w = weight [N]

m = mass = 0.06 [kg]

g = gravity acceleration = 10 [N/kg]

Therefore:

w=0.06*10\\w=0.6[N]

By Hooke's law we know that the force in a spring can be calculated by means of the following expression.

F=W\\F = k*x

where:

k = spring constant [N/m]

x = deformed distance = 6 [cm] = 0.06 [m]

We can find the spring constant.

k= F/x\\k=0.6/0.06\\k=10 [N/m]

Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.

F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]

Since this force is equal to the weight, we can now determine the gravitational acceleration.

F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]

6 0
3 years ago
An electrical heater is used to supply 245.0 J of energy to a 15.0 g sample of aluminum, originally at 310.0 K. Determine the fi
Softa [21]

Answer:

T_f=328.1 K

Explanation:

To determine the final temperature of the sample, we use the specific heat formular as follows:

Q=mCp(T_f-T_0)\\T_f=\frac{Q}{mCp} +T_{0}\\mol Al= \frac{15g}{26.98gmol^{-1}}=0.555 mol\\T_f=\frac{245.0J}{0.555mol\times24.35Jmol^{-1}K^{-1}} +310.0K\\T_f=328.1 K

Finally, the temperature of the aluminium sample has raised 18 K.

8 0
3 years ago
Two students have fitted their scooters with the same engine. Student A and his
sammy [17]

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

<h3>Force applied by each student</h3>

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

  • m is mass
  • a is acceleration

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

3 0
2 years ago
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