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3 years ago

Delia worked for 45 minutes on her oil painting She took a break at 10:35 A.M. at what did she start working on the painting

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

8 0

Answer:

She started working at 9:50 am.

9:50 + 45 = 9:95 convert to where 60 minutes is a hour and you get 10:35 am.

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Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2

pshichka [43]

$a_n_+_1=-4a_n_+_2$

dividing both sides by -4, we get:

$a_n_+_2=- \frac{a_n_+_1}{4}$

this means, each term is its previous term divided by -4.

now we can construct the sequence as follows:

$a_1=2$

$a_2=- \frac{a_1}{4}= - \frac{2}{4}= -\frac{1}{2}$

$a_3=- \frac{a_2}{4} =- \frac{ \frac{1}{2} }{4}=- \frac{1}{8}$

$a_4=- \frac{a_3}{4}=- \frac{ \frac{1}{8} }{4}=- \frac{1}{32}$

Answer: the last term is -1/32

3 0

3 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

6 0

2 years ago

Fifteen minus three to the power of two

Stells [14]

Your first answer is correct but I’m not sure if your second is. But I’m leaning towards it is not correct.

Hope this helps!

(Don’t forget to mark branliest if it is correct :) )

5 0

3 years ago

Read 2 more answers

What is the greatest common factor of 10, 20, and 50?

Viefleur [7K]

Answer:

Step-by-step explanation:

first you need to find the prime factors of the three numbers

ex:

prime factor of 18= $2*3*3$

prime of 24= $2*2*2*3$

there is one 2 and one 3 in common

greatest common multiple 2*3=6

so the greatest common multiple is ten because it is the only one that can divide between all three evenly.

$10=10/10=1\\20=20/10=2\\50=50/10=5$

so 10 is your answer

6 0

3 years ago

The piecewise function h(x) is shown on the graph.

Artemon [7]

Step-by-step explanation/Answer:

The value for h(3) is 1.

Coordinate (3,1)

The value on h(3) is located in the last part of the piecewise function, which starts at (1,3) until (4,0). To know the exact image of h(3), we can find the function that belongs to that piece of line, and then calculated the asked value.

So, to calculate the equation, we first have to find the slope with its definition, and then we'll use the point-slope formula to find the equation:

Therefore, the coordinates is (3,1), that is, the value for h(3) is 1.

3 0

3 years ago

Read 2 more answers