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WINSTONCH [101]
3 years ago
11

Which segment is skew to bd

Mathematics
1 answer:
AVprozaik [17]3 years ago
6 0
<span>Skew lines exist in a three-dimensional geometry. These are lines that are not parallel with each other but do not intersect. They are lines that do not lie on the same plane or non-coplanar. Hope this helps since there is no figure attached to the problem. </span>
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Complete the solution of the equation. Find the<br> value of y when x equals -18.<br> -3x - y = 56
Reil [10]

Answer:

y = -2

Step-by-step explanation:

8 0
3 years ago
What is 34% of 60000000
Ainat [17]

(Lets hope i'm right :p)


The first thing you do is make "34%" into a fraction. That would be 1/34.

After, you would multiply.


1/4 x 60000000/1 = ?

(Use cross multiply if you know)

60000000 divided by 4 = 15000000

1/1 x 15000000/1 = 15000000/1 OR 15000000


Answer: 15000000/1 or 15000000

<em>Tell me if i'm wrong so I can prevent this in the future! Have a lovely day!</em>

                                                                                                     ~Pooch ♥


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3 years ago
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Lindsey purchased a random sample of 25 tomatoes at the farmers market. The 95% confidence interval
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3 & 5

Step-by-step explanation:

3 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
2 years ago
A class quiz has 5 true or false questions the correct answers are t,t,f,f,
raketka [301]
I’m not sure what you are trying to say in this problem?
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2 years ago
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