Explanation:
NH₄F+ AICI₃, → NH₄CI + AlF₃
NH,F: in ionic form
NH₄⁺ + F⁻ = NH₄F
AICI in ionic form:
Al³⁺ + Cl⁻ = AlCl₃
NH Cl in ionic form:
NH₄⁺ + Cl⁻ = NH₄Cl
Al F in ionic form:
Al³⁺ + F⁻ = AlF₃
NH₄F+ AICI₃, → NH₄CI + AlF₃
Now we have to balance the equation with respect to the atoms:
aNH₄F+ bAICI₃, → cNH₄CI + dAlF₃
for N: a = c
H: 4a = 4c
F: a = 3d
Cl: 3b = c
let a = 1
c = 1
b =
d =
Therefore we can imply that:
a = 3, b = 1 , c = 3 and d = 1 if we multiply through by 3
3NH₄F+ AICI₃, → 3NH₄CI + AlF₃
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Correct answer is 20 kJ; 50 kJ
potential energy is resting energy, that peak that's 75 kJ would be the kinetic energy
Answer:
When Zinc reacts with hydrochloric acid the following reaction takes place:
Zn+2HCl→ZnCl
2
+H
2(g)
↑
Here 1 molecules of hydrochloric acid taking part in the reaction,the number of molecules of hydrogen produced in the reaction.
4molesofHCl×
2molesofHCl
1moleofH
2
=2molesofH
2
Moles of NaCl
Molality
i is vant Hoff factor
For NaCl vant Hoff factor is 2( Actually 1.9)
Answer: 0.52 L of 15 M will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base