Explanation:
b. Bromo cyclopentane + HBr
Answer:
-10778.95 J heat must be removed in order to form the ice at 15 °C.
Explanation:
Given data:
mass of steam = 25 g
Initial temperature = 118 °C
Final temperature = 15 °C
Heat released = ?
Solution:
Formula:
q = m . c . ΔT
we know that specific heat of water is 4.186 J/g.°C
ΔT = final temperature - initial temperature
ΔT = 15 °C - 118 °C
ΔT = -103 °C
now we will put the values in formula
q = m . c . ΔT
q = 25 g × 4.186 J/g.°C × -103 °C
q = -10778.95 J
so, -10778.95 J heat must be removed in order to form the ice at 15 °C.
Answer:
60 ml
Explanation:
Now, we know that density = mass/volume
Mass of aluminium = 67.5 g
volume of aluminium =?
density of aluminium = 2.70 g/mL
volume of aluminium = mass/density = 67.5/2.70 = 25 ml
Since volume of water in the cylinder = 35 ml
The water rises to ; 35 ml + 25 ml = 60 ml
<u>Answer:</u>
Those cells that develop differently are referred to Specialised Cells.
<u>
</u><u>Explanation:</u>
Specialised cells are the one that is assigned to perform a specific role. Every specialised cell in the body is assigned to do their own job. The special features in them help them to perform their functions effectively.
Examples of specialised cells are- red blood cells (they are responsible to carry oxygen in the body), nerve cells (specialises in transmitting electrical signals) and muscle cells (brings body parts together).
Answer: The mass of the sample will be 1417.7 grams.
Explanation:
We are given:
This means that 1 mole of NaCl has an enthalpy of fusion of 30.2 kJ
1 mole of NaCl has a mass of 58.44 grams.
So, 30.2 kJ of heat is require for a mass 58.44 grams of NaCl
So, 732.6 kJ of heat will be required for = 
= 1417.65 grams of NaCl.
Hence, the mass of NaCl sample will be 1417.7 grams.
