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Arada [10]
3 years ago
11

A 2-yard piece of copper wire costs $69.48. What is the price per foot?

Mathematics
2 answers:
Jobisdone [24]3 years ago
5 0
Susan's grandpa was fibbing again your grandma and i together we are over 150 years old if her grandpa is 17 and her grandma is 68 what is the real sum of their ages
Temka [501]3 years ago
3 0
$69.48/6=11.58
3 feet in a yard
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Your Answer is 2/7. I hope this helped
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What is the circumference of the base
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43.96

Explanation:

C=2pi(r)
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14 x 3.14 = 43.96
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3 years ago
Read 2 more answers
Sorry if its blurry <br>Need help with this almost done
JulijaS [17]

Answer:

the number of pencils she bought

Step-by-step explanation:

p is just another variable like x or y

3 0
2 years ago
The electrician charges $50 per visit plus $12 per hour of work. Steve hires the electrician to do some work for his house. If S
TEA [102]

Answer:

12.5 hours

Step-by-step explanation:

budget: 200

fix cost: 50

hourly rate: 12

hours: ?

----

First we deduct the fix 50 dollars cost from the total budget.

Then we divide the remaining amount with the hourly rate

( 200 - 50 ) / 12 = ?

? = 12.5 hours

8 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
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