Question

PLEASE HURRY THANK YOU

Answer 1

Option B

The probability of one of the coins landing on tails and two of them landing on heads is $\frac{3}{8}$

Solution:

To find:  probability of one of the coins landing on tails and two of them landing on heads

The probability of an event is given as:

$probability =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}$

The outcomes are given as:

(H, H, H), (H, H, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T)

Here, total number of possible outcomes = 8

Favorable outcomes = one of the coins landing on tails and two of them landing on heads

Favorable outcomes = (H, H, T) , (H, T, H) , (T, H, H)

Therefore, number of favorable outcome = 3

Thus probability is given as:

$probability = \frac{3}{8}$

Thus option B is correct