Option B
The probability of one of the coins landing on tails and two of them landing on heads is ![\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D)
<em><u>Solution:</u></em>
To find: probability of one of the coins landing on tails and two of them landing on heads
<em><u>The probability of an event is given as:</u></em>
![probability =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}](https://tex.z-dn.net/?f=probability%20%3D%5Cfrac%7B%5Ctext%20%7B%20number%20of%20favorable%20outcomes%20%7D%7D%7B%5Ctext%20%7B%20total%20number%20of%20possible%20outcomes%20%7D%7D)
<em><u>The outcomes are given as:</u></em>
(H, H, H), (H, H, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T)
Here, total number of possible outcomes = 8
Favorable outcomes = one of the coins landing on tails and two of them landing on heads
Favorable outcomes = (H, H, T) , (H, T, H) , (T, H, H)
Therefore, number of favorable outcome = 3
Thus probability is given as:
![probability = \frac{3}{8}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7B3%7D%7B8%7D)
Thus option B is correct