Answer:
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Step-by-step explanation:
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hope its helps you
Answer:
A= 0,2
B= 0,2
C= 0,4
D=0,2
Step-by-step explanation:
We know that only one team can win, so the sum of each probability of wining is one
P(A)+P(B)+P(C)+P(D)=1
then we Know that the probability of Team A and B are the same, so
P(A)=P(B)
And that the the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)
Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2
Now if we use the first formula:
P(A)+P(B)+P(C)+P(D)=1
P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1
0,5 P(A)+0.9=1
0,5 P(A)= 0,1
P(A)= 0,2
P(B)= 0,2
P(C)=0,4
P(D)=0,2
Answer:
Step-by-step explanation:
First you need to convert it to a linear expression.
3x - y = 4
+3x +3x
-1y = 3x + 4
--- ----- -----
-1 -1 -1
y = -3x -4
6x - 2y = 7
-6x -6x
-2y = -6x + 7
---- ----- -----
-2 -2 -2
y = 3x - 3.5
-3x - 4 = 3x - 3.5
+3x +3x
-4 = 6x - 3.5
+3.5 +3.5
-0.5 = 6x
----- -----
6 6
-0.5
------ = x
6
X +(x+2) + (x+4) = 5(x+2)-18
3x+6 = 5x+10-18
3x+6 = 5x-8
3x=5x-14
-2x=-14
x=7
(x+2) =9
(x+4) =11
7 + 9+ 11 =27
5(9)-18 =45-18 =27
3 numbers are 7, 9 & 11