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myrzilka [38]
2 years ago
15

Which of the following reactions would NOT have a ""proton transfer step"" in the reaction mechanism: A 2-bromo-2-methylbutane +

​​ 2-methyl-2-butanol B 2-bromobutane + NaOH ​​ (E)-2-butene C 1-bromobutane + NaOMe ​​ methoxy butane D 2-bromo-2-methylbutane + tert-butoxide ​​ 2-methyl-1-butene

Chemistry
1 answer:
TiliK225 [7]2 years ago
6 0

<u>Answer: </u>

Reaction C

<u>Explanation: </u>

For reaction A) we have the production of alcohol by the action of the water that attacks the tertiary carbocation produced by the leaving of Br. In the last step we will have the proton transfer (figure 1).

For B) the proton transfer step is given in the double bond formation due to the attack of the hydroxle group (figure 2).

In C we have an Sn2 reaction. Therefore, the reaction takes place in only one step without the opportunity of a proton transfer step (figure 3).

Finally for D we have an elimination reaction in which the tert-butoxide molecule will remove hydrogen (proton transfer step) from the carbocation to produce an alkene (figure 4).

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Conclusion Questions:
Lerok [7]
That’s the question?
5 0
2 years ago
A 10.5 mL sample of vinegar, containing acetic acid, was titrated using 0.460 M NaOH solution. The titration required 19.13 mL o
laila [671]

Explanation:

Step 1:

A good first step for a problem like this is to write down the chemical formula and balance it.

It appears here that we have 10.5 mL of vinegar, which IS acetic acid, and 19.13 mL of 0.460 M NaOH. That will give us the following balanced chemical equation:

CH3COOH + NaOH ------> NaCH3COO + H2O

All of the constituents come out to a value of 1, conveniently.

Step 2:

Since all of our stoichiometric coefficients are one, we can use a shortcut to answer this equation. I don't know if it has a name, but I just call it the titration formula. It goes something like this:

M1 * V1 = M2 * V2

M stands for Molarity and V stands for volume. 1 and 2 being the before the reaction and after the reaction.

So, our M1 for this is going to be what the question says was used for this titration. That's 0.460M NaOH.

Our V1 is going to be the initial volume of the sample, which was 10.5 mL

Our V2 is going to be 19.13, which is the volume when we're finished.

It's clear that we don't know M2, so let's find it.

Keep in mind that it's easier to convert to liters pretty much always, so I've done that by dividing the mL values each by 1000.

Using some algebra, we can see that we now have:

0.460 M * 0.0105 L = x M * 0.01913 L

Which goes to:

\frac{0.00483mol}{0.01913L} = 0.252 M

<h3>So our M2, the molar concentration of acetic acid in this vinegar, is equal to 0.252 M. </h3>
3 0
3 years ago
The attractions that allow molecules of krypton to exist in the solid phase are due to:
OLga [1]

Answer:

4) Van der waals forces

Explanation:

Krypton (Kr) belongs to the noble gas group and has fully filled valence orbitals. In the solid phase, Kr exists as a white solid with a face centered cubic structure.

Intermolecular forces of attraction from the strongest to the weakest include:

Ionic > hydrogen bonding > dipole-dipole > london dispersion

Kr is monoatomic and non-polar. When fully filled (stable) valence orbitals of 2 Kr atoms approach each other in close proximity they experience a repulsive force which prevents the formation of strong bonds. Thus, the only force of attraction in Kr is the long range weak Van Der Waals force also known as the london dispersion force.

7 0
3 years ago
An element has an atomic number of 30. How many protons and electrons are in a neutral atom of the element? A. 30 protons, 30 el
Minchanka [31]
Atomic number shows the number of protons in an atom's nucleus. If the atomic number is 30, then it has 30 protons. The question says it is neutral, so it must have the same amount of protons and electrons.

A is the correct answer based on this. 
7 0
3 years ago
Which of the following elements has the highest electronegativity? beryllium iodine calcium nitrogen
juin [17]

Answer: Option (d) is the correct answer.

Explanation:

An atom or element which has the ability to readily gain an electron will have high electronegativity.

Both Beryllium and Calcium are alkaline earth metals and hence they are electropositive in nature.

Whereas both iodine and nitrogen are electronegative in nature. But across the period there is an increase in electronegativity and down the group there is a decrease in electronegativity.

Nitrogen belongs to period 2 and iodine belongs to the bottom of group 17. Thus, we can conclude that nitrogen is more electronegative than iodine.

8 0
3 years ago
Read 2 more answers
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