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3 years ago

The total number of electrons in one mole of fluorine molecules (F2) is

1 answer:

3 0

Fluorine's atomic number is 9, meaning it has 9 protons and 9 electrons in per atom. One mole is 6.0x10^23, so your answer is 4.

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Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1

givi [52]

According to Hasselbach-Henderson equation:

$pH=pK_{a}+log\frac{[A^{-}]}{[HA]}$

Here, $[A^{-}]$ is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is $CH_{3}COOK$ and acid is $CH_{3}COOH$ thus, Hasselbach-Henderson equation will be as follows:

$pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}$ ...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{2}{1}=5.06$

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{3}=4.28$

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{5}{1}=5.45$

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{1}=4.76$

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{10}=3.76$

Therefore, pH of solution is 3.76.

4 0

3 years ago

What is the mass number of an atom that contains 12 protons, 14 neutrons, and 12 electrons? *

Yuri [45]

The mass number of an atom : 26

<h3>Further explanation</h3>

Given

12 protons, 14 neutrons, and 12 electrons

Required

The mass number

Solution

Inside the atom there are 3 sub-particles, namely protons, neutrons and electrons. Protons and electrons are present in the atomic nucleus while electrons move around the atomic nucleus through energy levels in the atomic shell

Atomic number = number of protons = number of electrons

Mass number = number of protons + number of neutrons

Input the value :

Mass number = 12 + 14

Mass number = 26

7 0

3 years ago

When 0.040 mol of propionic acid, c2h5co2h, is dissolved in 750 ml of water, the equilibrium concentration of h3o+ ions is measu

WITCHER [35]

Answer is: Ka for propanoic acid is 6,57·10⁻⁵.
Chemical reaction: C₂H₅COOH(aq) + H₂O(l) ⇄ C₂H₅COO⁻(aq) + H₃O⁺(aq).
n(C₂H₅COOH) = 0,04 mol.
V(C₂H₅COOH) = 750 mL = 0,75 L.
c(C₂H₅COOH) = 0,04 mol ÷ 0,75 L.
c(C₂H₅COOH) = 0,053 mol/L = 0,053 M.
[C₂H₅COO⁻] = [H₃O⁺] = 1,84·10⁻³ M = 0,00184 M.
[HCN] = 0,053 M - 0,00184 M = 0,0515 M.
Ka = [C₂H₅COO⁻] · [H₃O⁺] / [C₂H₅COOH].
Ka = (0,00184 M)² / 0,0515 M.
Ka = 6,57·10⁻⁵.

3 0

3 years ago

What is one way that fission and fusion are similar?

nignag [31]

The Correct Answer Is Both Processes Produce Energy From Mass.

8 0

4 years ago

Read 2 more answers

A flask contains 5.0g of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the v

DaniilM [7]

Answer:

The volume of the neon gas is 17.07 L.

Explanation:

The ideal gas equation describes the relationship among the four variables P, V, T, and n. An ideal gas is a hypothetical gas whose pressure-volume-temperature behavior can be completely accounted for by the ideal gas equation.

In order to calculate the volume, first we need to convert the grams of neon to moles:

28.18 g Ne ------ 1 mol Ne

5.0 g Ne---------- x= 0.25 mol Ne

Now, using the ideal gas equation we calculate the volume:

$pV= nRT$

$V= nRT ÷ p$

$V= (0.25 mol × 0.082 L.atm/mol.K × 308.15 K ÷ 0.37 atm$

V= 17.07 L

6 0

3 years ago