Missing in your question :
Concentration by (M):
Xy: y: X
initial 0.2 0.3 0.3
change +X -X -X
equilibrim (0.2+x) (0.3-x) (0.3-x)
according to Kc formula: when Kc = 0.2
Kc = [XY]/[X]*[Y]
0.2 = (0.2+x) / (0.3-x)*(0.3-x)
0.2=(0.2+x) / (0.3-x)^2 by solving this equation
0.2*(0.3-x)^2 = 0.2+x
0.2* (0.09-0.6x+x^2)= 0.2 +x
0.0018 - 0.12 X +0.2X^2 = 0.2 + X
0.2X^2 -1.12 X -0.1982 = 0
∴X= 0.17
∴[XY] = 0.2 + 0.17 = 0.37 m
∴[X] = 0.3 - 0.17 =0.13 m
∴[y] = 0.3 - 0.17 = 0.13 m
A metallic bond is a force that holds atoms together in a metallic substance.
Answer:
A-) 8 Atoms
B-) 6 Atoms
C-) 16 Atoms
D-) 24 Atoms
Explanation:
A) Na (1 Atom) C2 (2 Atoms) H (1 Atom)O4 (4 Atoms)
1 + 2 + 1 + 4 = <em>8 Atoms</em>
B) H (1 Atom) 2F( 2 Atoms) 2B (2 Atoms) Li (1 Atom)
1 + 2 + 2 + 1 = <em>6 Atoms</em>
C) 2 He2 (2 Atoms) P (1 Atom) S1 (Atom) O4 (4 Atoms)
2 . ( 2 + 1 + 1 + 4 ) = 2 . 8 = <em>16 Atoms</em>
D) 3 He2 (2 Atoms) O4 (4 Atoms) P (1 Atom) H (1 Atom)
3 . (2 + 4 + 1 + 1 ) = 3 . 8 = <em>24 Atoms</em>
<em>It looks messy but I hope it will be understood.</em>
<em>If I have any inaccuracies please let me know.</em>
<em>Have a nice day and never stop questioning!</em>
The formula for iron (II) sulfate hexahydrate
FeH12O10S