Which is a way ro write nine eighths?

Kaylee decided to donate 30% of her savings if she has $238 in her savings account about how much will she Donate

skelet666 [1.2K]

Answer:

$71.40

Step-by-step explanation:

Turn the percentage 30 to a decimal, which is 0.3 then multiply it by 238 to get 71.4

5 0

4 years ago

Marks ratio is 3 tablespoons sugar to 2 tablespoons milk.Sharri is using 4 tablespoons of sugar to 3 tablespoons of milk.Eva is

SpyIntel [72]

Eva because 3:2 = 9:6 because when they multiply by 3 on each ratio

8 0

3 years ago

A bank features a savings account that has an annual percentage rate of 3.5% with interest compounded quarterly. Vanessa deposit

vazorg [7]

Answer:

APY = 0.04 or 4%

Step-by-step explanation:

Given the annual percentage rate of 3.5% that is compounded quarterly, and a principal of $6,500:

We can use the following formula to solve for the annual percentage yield (APY):

$APY = (1 + \frac{r}{n})^n - 1$

where r = interest rate = 3.5% or 0.035

n = number of compounding periods per year = 4

We can plug in the values into the equation:

$APY = (1 + \frac{r}{n})^n - 1$

$APY = (1 + \frac{.035}{4})^4 - 1$

$APY = (1 + 0.00875)^4 - 1$

$APY = (1.00875)^4 - 1$

APY = 1.03546 - 1

APY = 0.04 or 4%

8 0

3 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$