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svetoff [14.1K]

3 years ago

13

2 thousands 7 tens dividido en 10

1 answer:

Nadya [2.5K]3 years ago

3 0

Answer: 207

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Express as a trinomial: (2x-3)(x 5)

Illusion [34]

I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.

1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.

(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2 $x^{2}$ )+(10x)+(-3x)+(-15)=2 $x^{2}$ +7x-15

(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2 $x^{2}$ )+(-10x)+(-3x)+(15)=2 $x^{2}$ -13x+15

Your answer is 2 $x^{2}$ +7x-15 or 2 $x^{2}$ -13x+15. Does that answer your question?

6 0

2 years ago

Flora is making salsa for a party. Every 1 cup of chopped tomatoes makes 2 3/4 cups of salsa. She uses 1 2/3 cups of tomatoes. H

pogonyaev

Answer:

4 $\frac{7}{12}$ cups of Salsa.

Step-by-step explanation:

Flora is making Salsa for a party.

Every 1 cup of chopped tomatoes makes 2 $\frac{3}{4}$ = $\frac{11}{4}$ cups of Salsa

She uses 1 $\frac{2}{3}$ = $\frac{5}{3}$ cups of tomatoes

1 $\frac{2}{3}$ cups of tomatoes makes:

$\frac{5}{3}$ × $\frac{11}{4}$ ÷ 1 = $\frac{55}{12}$ = 4 $\frac{7}{12}$ cups of Salsa.

5 0

2 years ago

Pls help With this question thank you

Lapatulllka [165]

Answer:

$CD=4 \text{ cm }$

Step-by-step explanation:

We have a similarity of triangles. Once the side BC and ED are parallel,

$\frac{BC}{AC} =\frac{ED}{AD}$

$\frac{10}{AC} =\frac{5}{4}$

Once $AC=AD+CD \Rightarrow AC=4+CD$

$\frac{10}{4+CD} =\frac{5}{4}$

$5CD+20=40$

$5CD=20$

$CD=4 \text{ cm }$

6 0

3 years ago

What is 6 [4•(72-63)÷3]

QveST [7]

<span>What is 6 [4•(72-63)÷3]?

</span><span>6 [4•(72-63)÷3]
</span>
=72

7 0

2 years ago

Use the power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonome

ratelena [41]

Answer:

$x = 0.175\cdot (1-\cos 4\cdot \theta)$

Step-by-step explanation:

Let use the following trigonometric identities:

$\sin^{2}\theta = \frac{1-\cos 2\cdot \theta}{2} \\\cos^{2}\theta = \frac{1+\cos 2\cdot \theta}{2}$

Then, the equation is simplified by substituting its components:

$x = 1.40\cdot \left(\frac{1-\cos 2\cdot \theta}{2} \right)\cdot \left(\frac{1+\cos 2\cdot \theta}{2} \right)$

$x = 0.35\cdot (1-\cos^{2}2\cdot \theta)$

$x = 0.35\cdot \sin^{2}2\cdot \theta$

$x = 0.35\cdot \left(\frac{1-\cos 4\cdot \theta}{2} \right)$

$x = 0.175\cdot (1-\cos 4\cdot \theta)$

7 0

3 years ago

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