2 thousands 7 tens dividido en 10

Mathematics

1 answer:

Nadya [2.5K]4 years ago

3 0

Answer: 207

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const2013 [10]

Answer:

Area of a trapezoid = ½(a + b)h, where a and b are the lengths of the parallel sides and h is its height.

From your information 20 = ½(2z + 3 + 6z – 1)z = ½(8z + 2)z = z(4z + 1)

Solve 20 = 4z² + z which is 0 = 4z² + z – 20 using the quadratic formula

Step-by-step explanation:

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Sin A tan A/ 1 - cos A = 1+ sec A

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$\text{L.H.S}\\\\=\dfrac{\sin A \tan A}{1- \cos A}\\\\\\=\dfrac{\sin A \cdot \tfrac{\sin A}{\cos A} }{ 1- \cos A}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;\left[\tan A = \dfrac{\sin A }{\cos A}\right]\\\\\\=\dfrac{\tfrac{\sin^2 A}{ \cos A}}{1- \cos A}\\\\\\=\dfrac{\sin^2 A}{\cos A(1-\cos A)}\\\\\\=\dfrac{1-\cos^2 A}{\cos A( 1- \cos A)}~~~~~~~~~~~~~~~~~~~~~~~~;[\sin^2 A + \cos^2 A = 1]\\\\\\$

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Please help -6(-5)+12

madreJ [45]

<span>-6(-5)+12
Multiply -6 by -5.
Note: Whenever you multiply or divide a negative number by another negative number, it automatically becomes a positive number.
30+12
Add
Final Answer: 42</span>

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