Name two pairs of adjacent angels and two pairs of vertical angels in figure

Mathematics

1 answer:

sashaice [31]4 years ago

3 0

Answer:

As in this case where the adjacent angles are formed by two lines intersecting we will get two pairs of adjacent angles (G + F and H + E) that are both supplementary. Two angles that are opposite each other as D and B in the figure above are called vertical angles. Vertical angles are always congruent

Step-by-step explanation:

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Will give brainliest

ehidna [41]

Answer:

25.047 or roughly 25.

Step-by-step explanation:

I solved it wrong the first time then i double check with wolframalpha and got the correct number.

We know that the area of the tile is 18 $\sqrt{3}$ and it makes a triangle, we also know the base and height. In this case the base is 2 $\sqrt{3}^{x/12}$ and the height is also given which is $\sqrt{3}^{\frac{x}{6} }$ .

Area of triangle = $\frac{bh}{2}$ ,

substituting we will end up with 18 $\sqrt{3}$ =( 2 $\sqrt{3}^{x/12}$ * $\sqrt{3}^{\frac{x}{6} }$ ) / 2

Here is the tricky part $\sqrt{x} = x^{\frac{1}{2} }$ , i totally forgot about that lol.

Simplifying: we will get 18 $\sqrt{3}$ = $3^{\frac{x}{8} }$

Now, in order to find the x, we will need to take the log of both sides.

$log18\sqrt{3} = \frac{x}{8} log3$

Solving for x we end up getting:

$8\frac{log18\sqrt{3} }{log3}$ = x

where x = 25.047.

To be honest I deserve a nobel prize not a brainliest lol.

Good question bro, take it easy.

5 0

3 years ago

A builder had been asked to lay an octagonal patio using square paving slabs. To do this, he cuts some of the bricks in half dow

Orlov [11]

Assuming you want an expression for the possible total area of the patio: if "completed" would be a rectangle of dimensions n, m: each must be >=3 to allow for octagonal corners. But each of the 4 corners must be missing, that's diagonals comprising (1/2)a^2, (1/2)b^2, (1/2)c^2, and (1/2)d^2, where a,b,c, and d must be variously limited and co-limited so as to allow at least 1 linear side of the original rectangle to be exposed. So A = (n*m)-(1/2)a^2-(1/2)b^2-(1/2)c^2-(1/2)d^2 as an expression.
Now, imagine replicating your possible (potentially irregular) octagons onto a plane and juxtaposing them so as to create a paved network. What geometric properties might such a network have? You now have a miniscule idea what nature does with silicate networked minerals, except that takes place in 3-D, with tetrahedra of SiO4 .

7 0

3 years ago

How do you solve this equation and check the solution 17=z-(-9)

Alexeev081 [22]

17=z-(-9) 17=z+9 17-9=z 8=z To check 17= 8-(-9) 17= 8 +9 17=17 it checks

5 0

4 years ago

-x^2+2xy when x= -3 and y= -2

natka813 [3]

Answer:

Step-by-step explanation:

$-(-3)^{2} +2(-3)(-2)=-9+12=3$