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wolverine [178]
3 years ago
8

Justin mixed two clear liquids together during an experiment and made the following observations: The mixed liquids decreased in

temperature without any refrigeration or other action to change the temperature. The color of the liquid changed to blue. Which statement best describes Justin’s experiment? A. A physical change occurred, and this caused the liquid’s chemical properties to change. B. A chemical change occurred, and this caused the liquid’s physical properties to change. C. A physical change occurred, so only physical properties changed. D. A chemical change occurred, so only chemical properties changed.
Chemistry
1 answer:
kvasek [131]3 years ago
5 0

Answer:

B

Explanation:

A chemical change occurred, and this caused the liquid’s physical properties to change.

when we read her experiment we can see that color changed to blue, it is because new products are formed. And the temperature cause this.

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atoms have no overall charge. this is because they contain equal numbers of positive protons and negative electrons

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For doping silicon with boron, silicon specimen was kept in gaseous atmosphere containing B2O3 that maintained the B concentrati
Kay [80]

Solution :

From Fick's law:

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=N_a$

Mass balance: Exits = Accumulation

-N_A A = \frac{dm}{dt}

-N_A A = \frac{dVp}{dt}

-N_A A = \frac{dV}{dt}p

-N_A A = \frac{dhA}{dt}

-N_A A = \frac{dh}{dt} \times Ap

From the last step, area cancels out and thus leaves :

-N_A  = \frac{dh}{dt} \times p

So now we can substitute the $N_A$ by the Fick's law

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=\frac{dh}{dt} p$

Substituting the values we get

$=\frac{-4 \times 10^{-13}}{0.0001} \times (3 \times 10^{26} - C_{A2}) = \frac{dh}{dt} \times 2.46$

$=-4 \times 10^{-9} \times( 3 \times 10^{26} - C_{A2}) = 0.0001 \times 2.46$

$= -7800 \times 4 \times 10^{-9}  \times (3 \times 10^{26}-C_{A2})=0.000246$$=-(3 \times 10^{26}-C_{A2}) = 7.8846 \times 100 \times \frac{1}{69.62} \times 6.022 \times 10^{23}$

$C_{A2} = 6.85 \times 10^{28} \ \text{ boron atoms} /m^3$

3 0
3 years ago
In a nucleotide, the nitrogenous base is attached to the sugar's _____ carbon and the phosphate group is attached to the sugar's
Anon25 [30]

Answer:

1' and 5' carbon.

Explanation:

DNA is the genetic material of almost all the living organisms but exceptions are involved in case of some viruses that contains RNA as their genetic material.

The DNA consists of the nitrogenous base, dexoyribose pentose sugar and the phosphate group. The base is attached with the sugar on the 1' position. The phosphate group is linked with the sugar at 5 position of the dexoyribose sugar.

Thus, the correct answer is 1' and 5' carbon.

6 0
3 years ago
Ultraviolet photoelectron spectroscopy (UPS) is an important analytical tool used to characterize the composition of materials i
Setler [38]

Answer:

The equation for the Kinetic Energy, KE_e, of the photo-emitted electrons is given as follows;

KE_e = h\cdot f- BE

Please find attached the required plot of the kinetic energy versus the frequency

Explanation:

The equation for the Kinetic Energy, KE_e, of the photo-emitted electrons is given as follows;

KE_e = h\cdot f- BE

Where:

h = Planck's constant = 6.63×10⁻³⁴ J·s

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f₀ = Threshold frequency for the material

The ionization energy is the energy required to free an electron from an isolated atom

4 0
3 years ago
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