The acid dissociation constant is 1.3 × 10^-3.
<h3>What is acid-dissociation constant?</h3>
The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;
Let the acid be HA;
HA + H2O ⇄ H3O^+ + A^-
since the pH of the solution is 2.57 then;
[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3
We can see that; [H3O^+] = [A^-] so;
Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)
Ka = 1.3 × 10^-3
Learn more about acid-dissociation constant: brainly.com/question/9728159
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2NaOH(aq) + H2SO4(aq) => Na2SO4(s) + 2H2O(l)
This is a neutralization reaction.
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Answer:
Option A, 931 Kg
Explanation:
As we know that weight is equal to the product of mass and acceleration due to gravity.
Thus,
m/s2
Substituting the given values in above equation, we get -
Kg
Hence, option A is correct
