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I am Lyosha [343]
3 years ago
9

Caclulate the pH for a solution with an [H+] = 9.75 x10-4

Chemistry
1 answer:
vovangra [49]3 years ago
3 0

Answer:

pH=3.01

Explanation:

pH=-log[H+]

=-log(9.74x10e-4)

=3.01

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An element A combines with element B. The electrons are transferred from the atom A to the atom B. .
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6 0
2 years ago
At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0480 g/l. what is the ksp of this salt at this
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Given the solubility of strontium arsenate is 0.0480 g/l . we have to convert it into mol/L by dividing it over molar mass (540.7 g/mol)
Molar solubility = 0.0480 / 540.7 = 8.9 x 10⁻⁵ mol/L
Dissociation equation:
Sr₃(AsO₄)₂(s) → 3 Sr²⁺(aq) + 2 AsO₄³⁻(aq)
                             3 s                   2 s
Ksp = [Sr²⁺]³ [AsO₄³⁻]²
       = (3s)³ (2s)²
       = 108 s⁵
Ksp = 108 (8.9 x 10⁻⁵) = 5.95 x 10⁻¹⁹ 
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2 years ago
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