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12345 [234]
3 years ago
8

Which of the following correctly describes one way that photosynthetic plants are involved in the carbon cycle? Choose 1 answer:

Choose 1 answer: (Choice A) A Photosynthetic plants can move carbon from the atmosphere into an ecosystem’s food web. (Choice B) B Photosynthetic plants break down the remains of organisms and release carbon dioxide into the atmosphere. (Choice C) C Photosynthetic plants move carbon-based molecules between consumers in an ecosystem
Chemistry
1 answer:
brilliants [131]3 years ago
7 0

Answer:

The correct answer is - (Choice A) A Photosynthetic plants can move carbon from the atmosphere into an ecosystem’s food web.

Explanation:

Photosynthesis is the process performed by photosynthetic or green plants in presence of light atmospheric carbon dioxide and water converted into glucose (6 carbon compound) and oxygen.

This glucose or sugar is utilized by the plants that are producers in the ecosystem food web. These producers are fed by consumers and carbon molecules transfer from all the trophic levels in the food chain or food web in the process.

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A compound has a percent composition of 81.71% C and 18.29% H. What is the empirical formula of this compound?
SCORPION-xisa [38]

Considering the definition of empirical formula, the empirical formula is C₃H₈.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, in first place you know the percent composition:

  • C: 81.71 %
  • H: 18.29%

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

  • C: \frac{81.71 grams}{12\frac{grams}{mole} }= 6.81 moles
  • H:\frac{18.29 grams}{1\frac{grams}{mole} }= 18.29 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

  • C: \frac{6.81 moles}{6.81 moles}= 1
  • H:\frac{18.29 moles}{6.81 moles}= 2.68 ≅ \frac{8}{3}

To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:

  • C: 1×3  =3
  • H:≅ \frac{8}{3}×3= 8

Therefore the C: H mole ratio is 3: 8

Finally, the empirical formula is C₃H₈.

Learn more about empirical formula:

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4 0
2 years ago
An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 5.00g of this compound produced 7.33g of
Olegator [25]
A combustion reaction involves an organic compound reacted with oxygen. The general chemical equation is as follows:
<span>
Organic Compound + Oxygen = CO2 + H2O

</span><span>To calculate the amount of C present in the original sample, we use the values given and assume that there is complete combustion that is happening.
</span><span>
7.33 g CO2 ( 1 mol CO2 / 44.01 g CO2)(1 mol C / 1 mol CO2) = 0.167 mol C

Therefore, 0.167 mol of C was originally in the sample.</span>
8 0
3 years ago
Read 2 more answers
What is the molar mass of a gas with a density of 3.50 g/L at a
Kruka [31]

Answer:

  • <u>104 g/mol</u>

Explanation:

Use the ideal gas equation:

      pV=nRT

Where:

  • p is pressure: 0.950atm
  • V is volume: unknown
  • n is number of moles: unknown
  • R is the universal constat of gases: 0.08206 atm.liter/ (K.mol)
  • T is the absolute temperature: 345K

Use the <em>molar mass</em> of the gas to include the density in the formula:

  • molar mass = mass in grams / number of moles

  • ⇒ mass in grams = number of moles × molar mass

  • density = mass in grams / volume

  • ⇒ density = number of moles × molar mass / volume

  • density = (n/V) × molar mass

  • ⇒ n/V = density / molar mass

Clear n/V from the gas ideal equation and subsittute with density/molar mass:

  • n/V = p/(RT)
  • density / molar mass = n/V
  • density/molar mass = p/(RT)
  • molar mass = density × RT / p

Now you can subsitute the data:

molar mass = (3.50g/liter) × 0.08206 atm.liter/(K.mol) × 345K / 0.950 atm

  • molar mass = 104.3 g/mol

  • Round to the nearest whole number: 104g/mol ← answer
3 0
3 years ago
The pH of a basic solution is 8.87. What is [H⁺]?
juin [17]
  • pH be x

\\ \rm\rightarrowtail -log[H^+]=8.87

\\ \rm\rightarrowtail log[H^+]=-8.87

\\ \rm\rightarrowtail [H^+]=10^{-8.87}

\\ \rm\rightarrowtail [H^+]=1.34

3 0
2 years ago
If you were asked to convert 3.5 moles of aluminum to grams, which of the following should you use for the conversion? . Select
Zolol [24]
To convert the given number of moles of aluminum to grams, we need to use the molar mass of the element as the conversion factor. Aluminum has a molar mass of 26.981 g/ mol. The answer to this problem is b. <span>fraction: 26.981 g Al over one mol Al. </span>
6 0
3 years ago
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