Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So


Given that
normal sampling distribution can not be used
<span>5t=3b+660....and ... 2t+5b=450
from the first we can see that t=(3b+660)/5 and using this value in the second...
(6b+1320)/5+5b=450 making all have common denominator..
6b+1320+25b=2250
31b=930
b=30...and since 2t+5b=450
t=150</span>
Answer:
f(g(x)) = x
Explanation:
In order to prove that one function is the inverse of the other, all you have to do is substitute in the main function with the inverse one and solve. If the result is x, then it is verified that one function is the inverse of the other.
Now for the given functions we have:
<span>f(x) =5x-25
</span><span>g(x) = (1/5)x+5
We want to prove that g(x) is the inverse of f(x).
Substitute in the above formula and compute the result as follows:
f(g(x)) = 5(</span>(1/5)x+5) - 25
= x + 25 - 25
= x
The final result is "x", therefore, it is verified that g(x) is the inverse of f(x)
Hope this helps :)
3.) A *the first one*
4.) C *the last one*