Answer:

Explanation:
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In this case, since the combustion of B2H6 is:

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:


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Could you show the characteristics?
Answer:
VH2SO4 = 145.3 mL
Explanation:
Mw BaO2 = 169.33 g/mol
⇒ mol BaO2 = 53.5g * ( mol BaO2 / 169.33 g BaO2) = 0.545 mol BaO2
⇒according to the reaction:
mol BaO2 = mol H2SO4 = 0.545 mol
⇒ V H2SO4 = 0.545 mol H2SO4 * ( L H2SO4 / 3.75 mol H2SO4 )
⇒V H2SO4 = 0.1453 L (145.3 mL)
The answer is C to achieve an octet of valence electrons so they become stable