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wariber [46]
1 year ago
12

What is the total pressure exerted by a mixture of 48.0 grams of CH4 and 56.0 grams of

Chemistry
1 answer:
Oksi-84 [34.3K]1 year ago
4 0

The pressure of the gas is obtained as 48 atm.

<h3>What is the total pressure?</h3>

Now we know that;

Number of moles of CH4 = 48.0 grams /16 g/mol = 3 moles

Number of moles of H2 =  56.0 grams/2 g/mol = 28 moles

Total number of moles present = 3 moles + 28 moles = 31 moles

Using;

PV =nRT

P = total pressure

V = total volume

n = total number of moles

R = gas constant

T = temperature

P = nRT/V

P = 31 * 0.082 * 286/15

P = 48 atm

Learn more about pressure of a gas:brainly.com/question/18124975

#SPJ1

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What causes the electrons to move and form static electricty?
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Answer:

Static electricity is the result of an imbalance between negative and positive charges in an object. ... When two materials are in contact, electrons may move from one material to the other, which leaves an excess of positive charge on one material, and an equal negative charge on the other.

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3 years ago
A piece of charcoal is found to contain
Naddika [18.5K]

Answer: The tree died 9709.46 years before.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant = 100

a - x = amount left after decay process = \frac{30}{100}\times 100=30

a) to find rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{5600years}=1.24\times 10^{-4}years^{-1}

b) to know the age

t=\frac{2.303}{1.24\times 10^{-4}}\log\frac{100}{30}

t=9709.46years

The tree died 9709.46 years before.

8 0
3 years ago
Percent of water in Na2CO3 • 10H2O
Troyanec [42]
Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15

Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass. 

→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63

Your answer will be about 63%. 

Hope this helped you out! :-)
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