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gogolik [260]
3 years ago
5

The density of water is about 1.0 g/mL at room temperature. Briefly explain how the density of an aqueous solution at room tempe

rature can be significantly less than 1.0 g/mL. Give an example of such a solution.
Chemistry
1 answer:
maksim [4K]3 years ago
7 0

Answer:

The density of water is about 1.0 g/mL at room temperature.

Briefly explain how the density of an aqueous solution at room temperature can be significantly less than 1.0 g/mL.

Give an example of such a solution.

Explanation:

That means 1.0mL of water weighs ---- 1.0g

If any other aqueous solution which has mass less than 1.0g will have density less than 1.0g.

For example aqueous solution of sulfuric acid has density 0.98g/mL.

That means 1mL of sulfuric acid has mass 0.98g.

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Cl is highly electronegative and will actually pull away 1 electron from sodium, forming an ionic bond. 
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Which best describes the role of a secondary consumer in a food web? (3 points)
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If we have equal masses of copper at 80oC and water at 20oC and we put them together, what is the final temperature?
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Answer:

The final temperature will be close to 20°C

Explanation:

First of all, the resulting temperature of the mix can't be higher than the hot substance's (80°C) or lower than the cold one's (20°C). So options d) and e) are imposible.

Now, due to the high heat capacity of water (4,1813 J/mol*K) it can absorb a huge amount of heat without having a great increment in its temperature. On the other hand, copper have a small heat capacity (0,385 J/mol*K)in comparison.

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<u>This analysis can be done because we have equal masses of both substances. </u>

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4 years ago
The pressure of a gas is reduced from 1200.0 mmHg to 1.11842 atm as the volume of its container is increased by moving a piston
Artist 52 [7]

Answer:

          \large\boxed{T_2=786.\ºC}

Explanation:

Ideal gases follow the combined law of gases:

         P_1V_1/T_1=P_2V_2/T_2

Where,

P_1,V_1, and{\text{ }T_1\text{ are the pressure, temperature, and volume of the gas a state 1}

P_2,V_2, and{\text{ }T_2\text{ are the pressure, temperature, and volume of the gas a state 2}

  • Pressure is the absolute pressure and its units may be in any system, as long as they are the same for both states.

  • Also, volume may be in any units, as long as it they are the same for both states.

  • Temperature must be absolute temperature, whose unit is Kelvin.

Your data are:

  • P₁ = 1200.00 mmHg
  • P₂ = 1.11842 atm
  • V₁ = 85.0 mL
  • V₂ = 350.0 mL
  • T₂ = ?
  • T₁ = 90.0ºC

<u>1. Conversion of units:</u>

  • P₁ = 1200.00 mmHg × 1.00000 atm / 760.000 = 1.578947 mmHg
  • T₁ = 90.00ºC + 273.15 = 363.15K

<u>2. Solution</u>

  • Clearing T₂, from the combined gas equation you get:

      T_2=P_2V_2T_1/(P_1V_1)

  • Substituting the data:

         T_2=1.11842atm\times 350.0ml\times 363.15K/(1.578947atm\times 85.0ml)

          T_2=1,059K

  • Convert to celsius:

         T_2=1059-273.15=786.\ºC

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