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3 years ago

What mass of HBO2 is produced from the combustion of 139.5 g of B2H6? Answer in units of g.

Chemistry

1 answer:

aliina [53]3 years ago

5 0

Answer:

$m_{HBO_2}=441.8gHBO_2$

Explanation:

Hello there!

In this case, since the combustion of B2H6 is:

$B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O$

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:

$m_{HBO_2}=139.5gB_2H_6*\frac{1molB_2H_6}{27.67gB_2H_6} *\frac{2molHBO_2}{1molB_2H_6} *\frac{43.82gHBO_2}{1molHBO_2}$

$m_{HBO_2}=441.8gHBO_2$

Best regards!

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Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

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Regards!

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