Answer:
is the total pressure of the tank.
Explanation:
Partial pressures of nitrogen = 
Partial pressure of oxygen = 
Total pressure of gases in the tank = P
Applying Dalton's law of partial pressures :
is the total pressure of the tank.
Answer:
30.62 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 55 L
Initial pressure (P₁) = 3.2 atm
Initial temperature (T₁) = 520 K
Final temperature (T₂) = 760 K
Final pressure (P₂) = 8.4 atm
Final volume (V₂) =?
The final volume of the gas can be obtained as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
3.2 × 55 / 520 = 8.4 × V₂ / 760
176 / 520 = 8.4 × V₂ / 760
Cross multiply
520 × 8.4 × V₂ = 176 × 760
4368 × V₂ = 133760
Divide both side by 4368
V₂ = 133760 / 4368
V₂ = 30.62 L
Therefore, the new volume of the gas is 30.62 L
<span>C. C4H8
Given that the number of moles of CO2 and H2O produced from the combustion are equal, that means for every carbon atom, there are 2 hydrogen atoms because CO2 has only 1 carbon atom and H2O has 2 hydrogen atoms. So let's look at the available choices and see which one is correct.
A. C2H2
This is a 1 to 1 ratio of carbon to hydrogen. Wrong answer.
B. C2H6
This is a 1 to 3 ratio of carbon to hydrogen. Wrong answer.
C. C4H8
This is a 1 to 2 ratio of carbon to hydrogen. Correct answer.
D. C6H6
This is a 1 to 1 ratio of carbon to hydrogen. Wrong answer.</span>
Data Given:
Time = t = ?
Current = I = 10 A
Faradays Constant = F = 96500
Chemical equivalent = e = 107.86/1 = 107.86 g
Amount Deposited = W = 17.3 g
Solution:
According to Faraday's Law,
W = I t e / F
Solving for t,
t = W F / I e
Putting values,
t = (17.3 g × 96500) ÷ (10 A × 107.86 g)
t = 1547.79 s
t = 1.54 × 10³ s
<span>Atomic Number 10 is Neon.
1s: 2
2s: 2
2p: 6
3s: 0
3p: 0
4s: 0
3d: 0
4p: 0
5s: 0</span>
