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3 years ago

What is happening if there is no overall energy change during a chemical reaction?

Chemistry

1 answer:

sergeinik [125]3 years ago

3 0

Answer:

The law of conservation of energystates that matter cannot be created or destroyed. Whether a chemical reaction absorbs or releases energy,there is no overall change in the amount of energy during the reaction.

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In this experiment, student groups ran repeated trials (5) and then averaged their data. ALL BUT ONE statement explains why

Colt1911 [192]

Answer:

its B

Explanation:

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3 years ago

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Which molecule is amphoteric?

frosja888 [35]

Answer:

The answer is B

Explanation:

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3 years ago

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What type of map should have a north arrow ,key , and map scale?

Radda [10]

<h2>Answer : Political Map</h2><h3>Explanation :</h3>

A political map is a kind of map which contains a north arrow, key and a map scale.

This kind of map usually indicates the governmental boundaries of countries, states, or any counties,

And, they give information about the location of major cities, also they usually include significant bodies of water.

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3 years ago

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The molar mass of sodium of chloride

wariber [46]

Answer:

22.989769 u.

Explanation:

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3 years ago

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An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol

mol H20= 66.2 g H₂O x $\frac{1 mol H2O}{18 g}$

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute= $\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}$

Xsolute= 0.059

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3 years ago