Answer:
The elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°
Step-by-step explanation:
From the ΔABC
AB = height of the building = 250 feet
BC = 800 ft
Angle of elevation = 
= 0.3125
°
Therefore the elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°
Answer:
2 remainder 5 ily
Step-by-step explanation:
If 9 is the radius and 20 is the height then it would be 5089.4 cm^3
Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
