We found a counterexample, so the statement is false.
<h3>
Is the statement true?</h3>
Let's use the matrix:
![\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-2%260%260%260%5C%5C0%261%260%260%5C%5C0%260%261%260%5C%5C%200%260%260%261%20%5Cend%7Barray%7D%5Cright%5D)
This is a 4x4 matrix with determinant equal to -2.
The inverse matrix is:
![\left[\begin{array}{cccc}1/2&0&0&0\\0&-1&0&0\\0&0&-1&0\\ 0&0&0&-1 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%2F2%260%260%260%5C%5C0%26-1%260%260%5C%5C0%260%26-1%260%5C%5C%200%260%260%26-1%20%5Cend%7Barray%7D%5Cright%5D)
If we multiply it by 2, we get:
![\left[\begin{array}{cccc}1&0&0&0\\0&-2&0&0\\0&0&-2&0\\ 0&0&0&-2 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%260%5C%5C0%26-2%260%260%5C%5C0%260%26-2%260%5C%5C%200%260%260%26-2%20%5Cend%7Barray%7D%5Cright%5D)
The adjoint of that is the original matrix, actually:
Which we already know, has a determinant of -2.
So the statement is false, as we found a counterexample.
If you want to learn more about matrices:
brainly.com/question/11989522
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Answer:
The answer is D
Step-by-step explanation:
I took the quiz lol:))
Finding the square root of a number is the inverse operation of squaring that number. Remember, the square of a number is thatnumber times itself. The perfect squares are the squares of the wholenumbers. The square root of a number, n, written below is the number that gives n when multiplied by itself.
m perpendicular to q is the correct answer
