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olga2289 [7]
3 years ago
9

A person who weighs 100 pounds on earth weighs 16.6Ib on the moon which is the independent variable

Mathematics
2 answers:
faltersainse [42]3 years ago
6 0
I'm pretty sure it's that the person weighs 100 pounds on earth
Pepsi [2]3 years ago
3 0
It would be at least 100 pounds
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What types of solutions does 6x^2 - 20x + 1 have?​
elena55 [62]

Answer:

2 real solutions

Step-by-step explanation:

We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:

b² - 4ac

If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.

Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:

b² - 4ac

(-20)² - 4 * 6 * 1 = 400 - 24 = 376

Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.

<em>~ an aesthetics lover</em>

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2 years ago
I need help with this please
natka813 [3]

Answer:

Step-by-step explanation:

Antelope, Montana:  

    21, 30, 42, 58, 70, 79

Range- 58     79-21= 58

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Quartile 3- 70

Interquartile Range- 40     70-30= 40

Augusta, Maine:

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Range- 47

Quartile 1- 32

Quartile 3- 66

Interquartile Range- 34

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3 years ago
Stephanie runs 8 feet per second.
jeyben [28]

Answer:

60 mins

Step-by-step explanation:

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3 years ago
Write the word sentence as an inequality. Then solve the inequality.
aleksley [76]
The answer is 4x>_-12. the underscore is the line under the “>”
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Read 2 more answers
Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

#SPJ1

4 0
1 year ago
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