3 years ago

Please help!!!!!!!!!!

1 answer:

4 0

Find the length of AB
AB²=20²+15²
AB²=400+225
AB²=625
AB=25

then find AD and BD
20²=AD·25
400=AD·25
AD=16
15²=BD·25
225=BD·25
BD=9
now use the geometric mean theorem (name?) to find CD
CD=√(9·16)
CD=√144
CD=12 cm

You might be interested in

Due in 10 minutes so

Vilka [71]

Answer:

(not B, C, or D)

6 0

3 years ago

WILL PICK BRAINIEST ANSWER AND u have to be my friend what is 5 1/3 + 4 2/5

Jobisdone [24]

The answer is 146/15.

8 0

3 years ago

Read 2 more answers

Are the triangles congruent?? Justify the answer

dimulka [17.4K]

Yes because they are at acute angels

6 0

2 years ago

Read 2 more answers

Need help please .The ares of the sector shown below is 59 yd^2 find the length of the radius. Round to the nearest whole number

Vinvika [58]

$\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=59\\ \theta =40 \end{cases}\implies 59=\cfrac{(40)\pi r^2}{360}\implies 59(360)=40\pi r^2 \\\\\\ \cfrac{59(360)}{40\pi }=r^2\implies \cfrac{531}{\pi }=r^2\implies \sqrt{\cfrac{531}{\pi }}=r\implies 13\approx r$

3 0

2 years ago

As duas bases de um tronco de pirâmide regular são hexagonais de lados 12 cm e 20 cm. Se a distância entre esses dois polígonos

Kamila [148]

Answer:

Step-by-step explanation:

i guess?

3 0

3 years ago