Answer:
<h2>Spending on infrastructure projects is an example of <u>Discretionary Fiscal Policy</u> aimed at increasing real GDP and employment.</h2>
Explanation:
- A discretionary fiscal policy basically refers to the manipulation or adjustment of various fiscal instruments by the government such as public taxes and government spending.
- The aim of discretionary fiscal policy is to adjust the overall macroeconomic condition in any country based on the existing or current situation or scenario.
- Now,infrastructural spending is part of fiscal policy or instrument to adjust the macroeconomic condition of the country as reflected by necessary modification in the GDP and employment level.Hence, higher infrastructural spending by the government would expectedly increase the residential and commercial construction projects in the country thereby,enhancing the GDP and the employment level in the country and boost the overall economy.
The difference between the monthly payment of R and S is equal to $48.53 by following the compound interest formula. Thus, Loan R's monthly loan amount is greater than Loan S.
<h3>What is a Compound interest loan?</h3>
Combined interest (or compound interest) is the loan interest or deposit calculated based on both the original interest and accrued interest from earlier periods.
![\rm\,For\,R\\\\P = \$\,17,550\\r\,= 5.32\%\\Time\,= n= 7\,years\\Amount\,paid= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\=[ 17,550 (1+\dfrac{5.32}{100\times12})^{7\times12} ]\\= [ 17,550 (\dfrac{12.0532}{12})^{84} ]\\\\= [ 17,550 (1.00443^{84} ]\\\\= \$ 25,440.48\\\\Total\,monthly\,payment = \rm\,\dfrac{25,440.48}{84}\\\\= \$\, $302.86\\\\](https://tex.z-dn.net/?f=%5Crm%5C%2CFor%5C%2CR%5C%5C%5C%5CP%20%3D%20%5C%24%5C%2C17%2C550%5C%5Cr%5C%2C%3D%205.32%5C%25%5C%5CTime%5C%2C%3D%20n%3D%207%5C%2Cyears%5C%5CAmount%5C%2Cpaid%3D%20%5BP%281%2B%5Cdfrac%7Br%7D%7B100%5Ctimes12%7D%29%5E%7Bn%5Ctimes12%7D%20%5D%5C%5C%3D%5B%2017%2C550%20%281%2B%5Cdfrac%7B5.32%7D%7B100%5Ctimes12%7D%29%5E%7B7%5Ctimes12%7D%20%5D%5C%5C%3D%20%5B%2017%2C550%20%28%5Cdfrac%7B12.0532%7D%7B12%7D%29%5E%7B84%7D%20%5D%5C%5C%5C%5C%3D%20%20%5B%2017%2C550%20%281.00443%5E%7B84%7D%20%5D%5C%5C%5C%5C%3D%20%5C%24%2025%2C440.48%5C%5C%5C%5CTotal%5C%2Cmonthly%5C%2Cpayment%20%3D%20%5Crm%5C%2C%5Cdfrac%7B25%2C440.48%7D%7B84%7D%5C%5C%5C%5C%3D%20%5C%24%5C%2C%20%24302.86%5C%5C%5C%5C)
![\rm\,For\,S =\\\\P=\,\$ 15,925\\r\,= 6.07\%\\T=n= 9\,years\\\\Amount\,paid\,= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\\\\= [15,925(1+\dfrac{0.0607}{12})^{9\times12} ]\\\\\\= [15,925(1+\dfrac{0.0607}{12})^{108} ]\\\\=[15,925(1.7247.84)} ]\\\\\= \$27,467.19\\\\Total\,monthly\,payment =\dfrac{\rm\,\$\,27,469.19}{108}\\\\= \$ 254.326\\\\](https://tex.z-dn.net/?f=%5Crm%5C%2CFor%5C%2CS%20%3D%5C%5C%5C%5CP%3D%5C%2C%5C%24%2015%2C925%5C%5Cr%5C%2C%3D%206.07%5C%25%5C%5CT%3Dn%3D%209%5C%2Cyears%5C%5C%5C%5CAmount%5C%2Cpaid%5C%2C%3D%20%5BP%281%2B%5Cdfrac%7Br%7D%7B100%5Ctimes12%7D%29%5E%7Bn%5Ctimes12%7D%20%5D%5C%5C%5C%5C%5C%3D%20%5B15%2C925%281%2B%5Cdfrac%7B0.0607%7D%7B12%7D%29%5E%7B9%5Ctimes12%7D%20%5D%5C%5C%5C%5C%5C%5C%3D%20%5B15%2C925%281%2B%5Cdfrac%7B0.0607%7D%7B12%7D%29%5E%7B108%7D%20%5D%5C%5C%5C%5C%3D%5B15%2C925%281.7247.84%29%7D%20%5D%5C%5C%5C%5C%5C%3D%20%5C%2427%2C467.19%5C%5C%5C%5CTotal%5C%2Cmonthly%5C%2Cpayment%20%3D%5Cdfrac%7B%5Crm%5C%2C%5C%24%5C%2C27%2C469.19%7D%7B108%7D%5C%5C%5C%5C%3D%20%5C%24%20254.326%5C%5C%5C%5C)
The difference between the monthly payment of R and S is equal to $48.53.
Hence, Loan R's monthly payment is greater than the loan's monthly payment by $48.53
To learn more about Compound interest, refer to the link:
brainly.com/question/14331235
Answer:
(a) E(X) = 3
(b) Var(X) = 12.1067
Explanation:
(a) E[X]
E[X]T = E[X]T=A + E[X]T=B + E[X]T=C
= (2.6 + 3 + 3.4)/3
= 2.6 (1/3) + 3(1/3) + 3.4(1/3)
= 2.6/3 + 1 + 3.4/3
= 3
(b) Var (X) = E[X²]−(E[X])²
Recall that if Y ∼ Pois(λ), then E[Y 2] = λ+λ2. This implies that
E[X²] = [(2.6 + 2.6²) + (3 + 3²) + (3.4 + 3.4²)]/3
= (9.36 + 12 + 14.96)/3
= 36.32/3
= 12.1067
Var(X) = E[X²]−(E[X])²
= 12 - 3²
= 12.1067 - 9
= 3.1067
Answer:
Journal Entries
Journal 1 :
Equipment $23,400 (debit)
Cash $23,400 (credit)
Being Purchase of Equipment
Journal 2 :
Cash $6,800 (debit)
Service Revenue $6,800 (credit)
Being Service rendered for Cash
Journal 3 :
Salaries Expense $2,100 (debit)
Cash $2,100 (credit)
Being Salaries expense paid
Explanation:
Narrations have been provided to explain the transaction. Remember to use the account titles provided in accounting for the transactions.
