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OverLord2011 [107]

3 years ago

8

HELPP PLZ WILL MARK BRAINLIEST AGAIN

1 answer:

disa [49]3 years ago

3 0

Answer:

The fifth and fourth one

Step-by-step explanation:

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What is the volume of the rectangular prism?

nignag [31]

Answer: 148.5 m3

Step-by-step explanation: I just took the quiz and got it right.

7 0

3 years ago

Multiply. a^5 . a . a^0 . a^-3

stiks02 [169]

$a^5 \cdot a \cdot a^0 \cdot a^{-3}=a^{5+1-3}\cdot 1 = a^3$

6 0

4 years ago

A series contains 18 numbers and has a sum of 4,185. The last number of the series is 275. What is the first number?

N76 [4]

If the series is made up of numbers in an arithmetic progression, you have

$\displaystyle\sum_{n=1}^{18}a_n=\sum_{n=1}^{18}(a_1+(n-1)d)=18a_1+153d=4185$

where $a_1$ is the first term and $d$ is the common difference between terms.

Since the last term in the series is $a_{18}=275$ , you have

$a_{18}=a_1+(18-1)d\implies a_1+17d=275$

Solve the system

$\begin{cases}18a_1+153d=4185\\a_1+17d=275\end{cases}$

and you'll find that the first term is $a_1=190$ (with $d=5$ ).

5 0

4 years ago

The price of a toy usually costs £50 is increased to £65 work out the percentage increase

I am Lyosha [343]

Answer:

Step-by-step explanation:

10% of 50 = 5

5% of 50 = 2.5

to get to 65 u do 5+5 = 10 so so far that is 20% but 20% only gets u to 60 so u add another 10% to reach 65

u have used 30% so the answer to yr question is 30%

<h2><em>does this help comment if / if not </em></h2>

8 0

3 years ago

A marketing firm wants to estimate how much root beer the average teenager drinks per year. A previous study found a standard de

Verdich [7]

Answer:

At least 832 teenargers must be interviewed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How many teenagers must the firm interview in order to have a margin of error of at most 0.1 liter when constructing a 99% confidence interval

At least n teenargers must be interviewed.

n is found when M = 0.1.

We have that $\sigma = 1.12$

So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 2.575*\frac{1.12}{\sqrt{n}}$

$0.1\sqrt{n} = 2.575*1.12$

$\sqrt{n} = \frac{2.575*1.12}{0.1}$

$(\sqrt{n})^{2} = (\frac{2.575*1.12}{0.1})^{2}$

$n = 831.7$

Rounding up

At least 832 teenargers must be interviewed.

4 0

3 years ago