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OverLord2011 [107]
3 years ago
8

HELPP PLZ WILL MARK BRAINLIEST AGAIN

Mathematics
1 answer:
disa [49]3 years ago
3 0

Answer:

The fifth and fourth one

Step-by-step explanation:

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What to do when a negative number is subtracted from a positive number?
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5 0
3 years ago
If the area of a rectangle with length (4x) is 4x2 + 12x, find the width.​
8090 [49]

Answer:

The width of a rectangle is: w = x+3

Step-by-step explanation:

Given

The length of rectangle = l = 4x

The area of rectangle = A = 4x² + 12x

To determine

The width of rectangle = w = ?

We know that the formula of the area of the rectangle is

A = wl

substitute A = 4x² + 12x and l = 4x in the equation to determine the width w of the rectangle

4x² + 12x = w×4x

w = [4x² + 12x] / [4x]

Factor 4x² + 12x:   4x(x+3)

w = [ 4x(x+3) ] /  [4x]

w = x+3

Therefore, the width of a rectangle is: w = x+3

3 0
3 years ago
I need help: what is this?
givi [52]

Answer:

9

Step-by-step explanation:

first you have to do the 1+2 to get 3 then you divide 6 by 2 and get 3 then you multiply 3x3 to get 9!

3 0
3 years ago
What is x in this equation −4.5= −0.5(x − 7.1)
Umnica [9.8K]

Answer:

x=16.1

Step-by-step explanation:

-4.5= -0.5(x -7.1)

Divide both sides by -0.5

9=x-7.1

Add 7.1 to both sides

16.1=x

Hope this helps!

7 0
3 years ago
Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho
Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

A_{g} = a.b

<u>Where:</u>

Ag: is the area of the rectangular garden

a: is the length of the rectangular garden = 50 cm = 0.5 m

b: is the width of the rectangular garden = 34 m

A_{s} = 540 m^{2}

<u>Where</u>:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

A_{s} + A_{g} = (a+2x)*(b+2x)

540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}

557 m^{2} = ab + 2x(a + b) + 4x^{2}

557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0

540 - 69x - 4x^{2} = 0                              

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

7 0
3 years ago
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