The area of a square or a rectangle (which is the shape of any room in a house) is:
Area = width x length
So, in this case:
Area = 51 m x 26 m = 1326 Sq meters. Which is pretty big if you ask me.
Anyhow, Ms Melcher needs to buy 1326 sq meters
Answer:
2nd option
Step-by-step explanation:
Given
3x³ - 15x² - 4x + 20
step 1 ( group the first/second and third/fourth terms )
(3x³ - 15x² ) + (- 4x + 20)
step 2 ( factor each group )
3x² (x - 5) - 4(x - 5) ← note factor of - 4 ( not + 4 )
step 3 ( factor out (x - 5) from each term )
(x - 5)(3x² - 4)
Since the shirt is 25 percent off your paying for 75 percent of the shirt. 0.75(36) is 27. The shirt will cost 27.00
Answer:
Well, you could always just put it onto a scale to find the mass. But assuming you aren't talking about a laboratory setting. sorry if its all werid i cant really put it into how it supposed to be
The general formula is:
ρ
=
m
V
where
ρ
is density in
g/mL
if mass
m
is in
g
and volume
V
is in
mL
.
So to get the mass...
m
=
ρ
V
Or to get the volume...
V
=
m
ρ
When you have the volume and not the density, and you want to find mass, you will need to find the density yourself. It's often readily available on the internet.
Just replace "[...]" with the object you want, and if it's not exactly what you need, consider it an estimate.
These days, you should be able to search for the density of any common object.
When you have the density and volume but not the mass, then just make up a mass.
You shouldn't need specific numbers to do a problem. You can always solve a problem in general and get a solution formula. If you need to, just make up some numbers that you know how to use.
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
<h3>What is the range of a quadratic equation?</h3>
In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.
x = - 9
y = (2 / 3) · (- 9)² - 6
y = 48
x = - 6
y = (2 / 3) · (- 6)² - 6
y = 18
x = - 3
y = (2 / 3) · (- 3)² - 6
y = 0
x = 0
y = (2 / 3) · 0² - 6
y = - 6
x = 3
y = (2 / 3) · 3² - 6
y = 0
x = 6
y = (2 / 3) · 6² - 6
y = 18
x = 9
y = (2 / 3) · 9² - 6
y = 48
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
To learn more on functions: brainly.com/question/12431044
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