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3 years ago

If State A is heated, which of the other two states would it more closely resemble? Explain.

1 answer:

6 0

Well if its a solid that your heating up then it would closely resemble a liquid and a gas. would be able to give a better answer if you provided more information

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1. A baseball is hit straight up at a speed of 45 meters per second.

Sidana [21]

Answer:

a) 103.32 m

b) 9.18 s

Explanation:

a) Let's use the knowledge that at the top of its trajectory, the baseball will have a final velocity of 0 m/s.

The acceleration due to gravity is -9.8 m/s², assuming the upwards direction is positive and the downwards direction is negative.

The initial velocity of the baseball is 45 m/s.

We are trying to find the vertical displacement of the baseball, Δx, and we have the variables v, a, and v₀.

Find the constant acceleration equation that contains all four of these variables:

v² = v₀² + 2aΔx

Substitute the known values into the equation.

(0)² = (45)² + 2(-9.8)Δx
0 = 2025 - 19.6Δx
-2025 = -19.6Δx
Δx = 103.32

The maximum height of the ball before it falls back down is 103.32 m.

b) Now we want to solve for time t. Find a constant acceleration equation that contains three known variables.

v = v₀ + at

Substitute known values into this equation.

0 = 45 + (-9.8)t
-45 = -9.8t
t = 4.59183673

Remember that this is only half of the baseball's flight since we are using the final velocity for when the ball is halfway through its trajectory.

To solve for the total time the baseball is in the air, double the time t we solved for.

2t = 9.18367346

The baseball is in the air for 9.18 s.

7 0

3 years ago

A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the h

zloy xaker [14]

Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

$m_{1}$ $u_{1}$ + $m_{2}$ $u_{2}$ = $m_{1}$ $v_{1}$ - $m_{2}$ $v_{2}$

$m_{1}$ = 3 kg, $u_{1}$ = 8 m/s, $m_{2}$ = 2 kg, $u_{2}$ = 0 m/s ( since it is at rest), $v_{1}$ = 2 m/s, $v_{2}$ = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x $v_{2}$ )

24 + 0 = 16 - 2 $v_{2}$

2 $v_{2}$ = 16 - 24

2 $v_{2}$ = -8

$v_{2}$ = $\frac{-8}{2}$

= -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

7 0

3 years ago

Assuming the earth is a uniform sphere of mass M and radius R, show that the acceleration of fall at the earth's surface is give

Keith_Richards [23]

Explanation:

The weight of an object on the surface of the earth is equal to the gravitational force exerted by the earth on the object.

$W=F_G$

$mg = G \dfrac{mM}{R^2}$

which gives us an expression for the acceleration due to gravity <em>g</em> as

$g = G\dfrac{M}{R^2}$

At a height h = R, the radius of a satellite's orbit is 2R. Then the acceleration due to gravity $g_h$ at this height is

$mg_h = G \dfrac{mM}{(2R)^2}= G \dfrac{mM}{4R^2}$

Simplifying this, we get

$g_h= G \dfrac{M}{4R^2} = \dfrac{1}{4} \left(G \dfrac{M}{R^2} \right) = \dfrac{1}{4}g$

3 0

3 years ago

A 7750 kg space probe, moving nose-first toward Jupiter at 179 m/s relative to the Sun, fires its rocket engine, ejecting 72.0 k

Reika [66]

Answer:

179.47m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute

7750(179)+72(230) = (7750+72)v

1,387,250+16560 = 7822v

1,403,810 = 7822v

v = 1,403,810/7822

v= 179.47m/s

Hence the final velocity of the probe is 179.47m/s

7 0

3 years ago

An organism that breaks down other living things when they die

jenyasd209 [6]

Fungi, bacterium
________________

4 0

3 years ago