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IgorLugansk [536]
4 years ago
14

Resistance increases with the length of the wire

Physics
1 answer:
Marta_Voda [28]4 years ago
4 0
If the length of the wire increases, then the amount of resistance will also increase.

1. Take a long piece of wire and cut it 10 pieces. Those pieces should all be different sizes, one should be 5___ (units in meter, cm, inches, etc.), and the next should be 5 ___ (units in meter, cm, inches, etc.) more than the one before.
2. Take one piece of wire and measure the resistance using ___ and record the results in the data table.
3. Repeat the previous step with all the pieces of wire.
4. Compare and contrast the results you have found.

I hope this helps a bit :)
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A stationary telescope monitoring a rocket ship observes the ship emitting flashes of light at 1-second intervals. If the ship b
LuckyWell [14K]

Answer:

The period of the telescope observe the light flashes is 1.2 sec.

(e) is correct option.

Explanation:

Given that,

Flashes of light = 1 sec

Speed of telescope =0.6c

We need to calculate the period of the telescope observe the light flashes

Using formula of period

t=\dfrac{T}{\sqrt{1-\dfrac{v^2}{c^2}}}

Put the value into the formula

t=\dfrac{1}{\sqrt{1-\dfrac{(0.6)^2\times c^2}{c^2}}}

t=\dfrac{1}{\sqrt{1-(0.6)^2}}

t=1.2\ sec

Hence, The period of the telescope observe the light flashes is 1.2 sec.

4 0
3 years ago
Two carts collide on a level, friction-less track. Cart A has a mass of 200 g and is initially stationary. Cart B has a mass of
Hatshy [7]
Convert 200 grams and 100 grams to 2kg and 1kg respectively 
momentum = mass x velocity 
momentum = 1 x 2 
initial momentum = 2 kg m/s
second scenario, cart b is moving -.5 m/s
momentum = mass x velocity
momentum = 1 x -.5
final momentum = -.5 kg m/s

momentum has to be the same in both scenarios so the 2 kg truck has to have a momentum of 2.5 kg m/s to push the total momentum of the second scenario to be 2 kg m/s like the first scenario

2.5 = 2 x velocity

velocity of cart a after the collision = 1.25 m/s

3 0
3 years ago
Um pequeno avião decola de um aeroporto em um dia nublado e é avistado mais tarde a 215 km de distância, em um curso que faz
hoa [83]
215 km is the answer
3 0
3 years ago
Read 2 more answers
The air in a hot-air balloon at 757 torr is heated from 17.0°c to 36.0°c. assuming that the moles of air and the pressure remain
evablogger [386]
Pv= nRT; n/V = p/rt; g/liter = moles/liters * 29.0g/mole
8 0
4 years ago
A basketball player shoots toward a basket 4.9 m away and 3.0 m above the floor. If the ball is released 1.8 m above the floor a
Zolol [24]

Answer:

  v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

          x = v₀ₓ t

          y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

         

the time to reach the basket is

        t = x / v₀ₓ

we substitute

        y- y₀ = \frac{ v_o \ x \ sin \theta  }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }

        y - y₀ = x tan θ - \frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }

         

we substitute the values

        3 -1.8 = 3.0 tan 60 - \frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}

        1.2 = 5.196 - 176.4 1 / v₀²

        176.4 1 / v₀² = 3.996

        v₀ = \sqrt{ \frac{ 176.4}{3.996} }

        v₀ = 6.64 m / s

6 0
3 years ago
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