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3 years ago

Resistance increases with the length of the wire

1 answer:

4 0

If the length of the wire increases, then the amount of resistance will also increase.

1. Take a long piece of wire and cut it 10 pieces. Those pieces should all be different sizes, one should be 5___ (units in meter, cm, inches, etc.), and the next should be 5 ___ (units in meter, cm, inches, etc.) more than the one before.
2. Take one piece of wire and measure the resistance using ___ and record the results in the data table.
3. Repeat the previous step with all the pieces of wire.
4. Compare and contrast the results you have found.

I hope this helps a bit :)

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Question 1 of 4 Attempt 4 The acceleration due to gravity, ???? , is constant at sea level on the Earth's surface. However, the

Evgen [1.6K]

Answer:

g(h) = g ( 1 - 2(h/R) )

*At first order on h/R*

Explanation:

Hi!

We can derive this expression for distances h small compared to the earth's radius R.

In order to do this, we must expand the newton's law of universal gravitation around r=R

Remember that this law is:

$F = G \frac{m_1m_2}{r^2}$

In the present case m1 will be the mass of the earth.

Additionally, if we remember Newton's second law for the mass m2 (with m2 constant):

$F = m_2a$

Therefore, we can see that

$a(r) = G \frac{m_1}{r^2}$

With a the acceleration due to the earth's mass.

Now, the taylor series is going to be (at first order in h/R):

$a(R+h) \approx a(R) + h \frac{da(r)}{dr}_{r=R}$

a(R) is actually the constant acceleration at sea level

and

$a(R) =G \frac{m_1}{R^2} \\ \frac{da(r)}{dr}_{r=R} = -2 G\frac{m_1}{R^3}$

Therefore:

$a(R+h) \approx G\frac{m_1}{R^2} -2G\frac{m_1}{R^2} \frac{h}{R} = g(1-2\frac{h}{R})$

Consider that the error in this expresion is quadratic in (h/R), and to consider quadratic correctiosn you must expand the taylor series to the next power:

$a(R+h) \approx a(R) + h \frac{da(r)}{dr}_{r=R} + \frac{h^2}{2!} \frac{d^2a(r)}{dr^2}_{r=R}$

6 0

3 years ago

Read 2 more answers

What is the metric unit of weight? Gram/pound/Newton/milliliter

coldgirl [10]

Weight is force.
The metric unit of force is the Newton.
1 Newton is the force needed to accelerate 1 kilogram at the rate of 1 m/s² .

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2 years ago

What is the free body for the platform

AURORKA [14]

Universal gravitional field free body for the platform

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3 years ago

Akia is balancing the equation Na + H2O NaOH + H2. He tries to find the coefficients that will balance the equation.

Pepsi [2]

<h3>Answer;</h3>

A: by counting up each individual atom and make sure the atom numbers are the same in the reactants and the products

<h3>Explanation;</h3>

According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation. Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.

Thus, any chemical equation requires balancing to ensure that the number of atoms of each element is equal in both sides of the equation. Balancing is a try and error process that ensures that the law of conservation of mass holds.

In this case, the balanced equation would be; 2Na +2H₂O → 2NaOH +H₂

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a system that uses reflected radio waves to detect objects and to measure their distance and speed is called

viktelen [127]

Such system is called RADAR (RAdio Detection And Ranging).

The Radar emits radio waves, that are reflected back by the object. Since the speed of the radio waves is known (their speed is equal to the speed of light), by measuring the time the waves take to come back to the source it is possible to infer the distance they covered, and so the distance of the object.

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