Answer:
c = 4,444.44
Explanation:
You have the following expression for the acceleration of the projectile:
(1)
s: distance to the ground of the projectile
To find the value of the constant c you use the following formula:
(2)
vo: initial velocity = 0 m/s
v: final speed = 200 m/s
Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m
You replace the expression (1) into the expression (2):
![v^2=2(cs)\Delta s](https://tex.z-dn.net/?f=v%5E2%3D2%28cs%29%5CDelta%20s)
You do the constant c in the last equation, then you replace the values of v, s and Δs:
![c=\frac{v^2}{2s\Delta s}=\frac{(200m/s)^2}{2(3m/s^2)(1.5m)}=4444.44](https://tex.z-dn.net/?f=c%3D%5Cfrac%7Bv%5E2%7D%7B2s%5CDelta%20s%7D%3D%5Cfrac%7B%28200m%2Fs%29%5E2%7D%7B2%283m%2Fs%5E2%29%281.5m%29%7D%3D4444.44)
Answer:
imma need a few answer choices so i can do my research
Explanation:
Please any thank you
The magnitude of charge on a proton and electron is the same, 1.602 x 10-19 C. Protons are +, and electrons -.
Answer:
electrons
Explanation:
An electric current is said to exist when there is a net flow of electric charge through a region. In electric circuits this charge is often carried by electrons moving through a wire. It can also be carried by ions in an electrolyte, or by both ions and electrons such as in an ionized gas (plasma).