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mrs_skeptik [129]
3 years ago
10

Given H(6,7) and I (-7,-6) if point G lies 1/2 of the way long line segment HI, Santiago argues that point G is located at the o

rigin. Is Santiago Correct. Justify your answer
Mathematics
1 answer:
amid [387]3 years ago
4 0
A point that is half way of line segment is the midpoint

Let (6, 7) be (x₁, y₁) and (-7, -6) be (x₂, y₂)

Mid point of HI = (\frac{x_1+x_2}{2},  \frac{y_1+y_2}{2})
Mid point of HI = (\frac{6+-7}{2},  \frac{7+-6}{0})
Mid point of HI = (- \frac{1}{2} ,  \frac{1}{2})

Santiago's statement is not correct
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I believe the answer is 8
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2 years ago
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One teacher wants to give each student 2/3 of a slice of pizza . If the teacher has 4 slices of pizza how many students will rec
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Answer: 6 students

Step-by-step explanation:

The teacher wants to give each student 2/3 of a slice of pizza but only has 4 slices to give.

If each student gets 2/3 out of 4 slices, the number of students receiving will be:

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3 years ago
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

I=sen(t)-t.cos(t)+C

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

cos(t)=\sqrt{1-sen^2(t)}

Entonces:

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Devolviendo los cambios:

I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C

Es la respuesta correcta

7 0
2 years ago
What is the midpoint of (4, 6) and (2, 10)?
Black_prince [1.1K]
I believe it is (3,8)
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What is the length of segment AC?
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Making a triangle with line segment AC as the hypotenuse, we see the two legs are 6 and 8 units. Using the Pythagorean theorem, 6^2=36 and 8^2=64. 36+64=100. The square root of 100 is 10, so the length of AC is 10 units. Please give me brainiest. Have a great day.

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