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ivanzaharov [21]
3 years ago
8

Let $ 500 be paid at the end of each quarter for 5 years. If the interest is earned rate of 13%, compounded quarterly, find the

future value of this ordinary annuity. a. $ 13,782.12 O b. $ 8,223.66 c. $ 21,315.22 O d. non of them e. $ 31,201.08
Mathematics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

Future value of annuity (FV) = $13,782.12 (Approx)

Step-by-step explanation:

Given:

Periodic payment p = $500

Interest rate r = 13% = 13%/4 = 0.0325 (Quarterly)

Number of period n = 5 x 4 = 20 quarter

Find:

Future value of annuity (FV)

Computation:

Future\ value\ of\ annuity\ (FV)=p[\frac{(1+r)^n-1}{r} ] \\\\Future\ value\ of\ annuity\ (FV)=500[\frac{(1+0.0325)^{20}-1}{0.0325} ] \\\\Future\ value\ of\ annuity\ (FV)=13,782.1219 \\\\

Future value of annuity (FV) = $13,782.12 (Approx)

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(02.02 MC) Triangle ABC is shown. A is at negative 2, 1. B is at negative 1, 4. C is at negative 4, 5. If triangle ABC is reflec
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Given:

The vertices of a triangle ABC are A(-2,1), B(-1,4) and C(-4,5).

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If a figure reflected over x-axis, then

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If a figure rotated 180 degrees about the origin, then

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B_2(1,-4)\to B'(-1,4)

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Therefore, the correct option is A.

6 0
3 years ago
Please help meee I need help
natta225 [31]

Answer:

5

6

Step-by-step explanation:

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the whole number that would be greater than 41/2 would be 5

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8 0
3 years ago
Which expression is equivalent to (x superscript four-thirds baseline x superscript two-thirds Baseline ) superscript one-third
Andrei [34K]
<h3><u>The equivalent expression is:</u></h3>

(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}

We have to find the equivalent expression

We can simplify the above expression using law of exponents

<em><u>Use the following law of exponents:</u></em>

a^m \times a^n = a^{m+n}

Therefore,

\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}

<em><u>Use another law of exponent</u></em>

(a^m)^n = a^{mn}

Therefore,

(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}

Thus the equivalent expression is found

5 0
3 years ago
Read 2 more answers
How to solve it and why
RideAnS [48]
6.

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Divide both sides by 4

x^2 + 1 = 0

Use the quadratic formula since this cannot be factored.

x = (-b +- sqrt(b^2 - 4ac))/(2a)

x = +- sqrt(-4(1)(1))/2

x = +- sqrt(-4)/2

x = +- 2i/2

x = +- i

x = i or x = -i

Quicker solution:

If you have x^2 = number, then

x = +- sqrt(number)

Once you get to

x^2 + 1 = 0

Subtract 1 from both sides

x^2 = -1

Apply the quick method

x = +- sqrt(-1)

x = +- i

8.

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Subtract 25 from both sides

x^2 = -25

Apply quick method

x = +- sqrt(25)

x = +- 5i

x = 5i or x = -5i
3 0
3 years ago
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