(2 − 3i) + (x + yi) = 6
We add the left hand side
(2+x) + (-3+y)i = 6
6 can be written in a+ib
6 can be written as 6 + 0i
(2+x) + (-3+y)i = 6 +0i
Now we frame 2 equations
2 + x= 6
-3 + y =0
Solve the first equation
2 + x = 6
Subtract 2 from both sides
x = 4
solve the second equation
-3 + y =0
Add 3 on both sides
y= 3
So x+yi is 4+3i
$819.20 is the answer considering each time the units increase by fours, it adds $204.80
Answer:
D) Amplitude: 2; period: π; midline: y = 1
Step-by-step explanation:
The question is much more easily answered from the graph than from the description of the graph.
The amplitude is the extent of the peak above the midline (2), or half the peak-to-peak value (4/2=2). The midline is the line halfway between the peaks (1). The period is the horizontal distance between peaks of the same polarity (π).
This looks like scalar matrix multiplication. The idea here is to multiply the scalar 3 by each item inside the matrix.
Doing so leads to the answer [3 -12 15 -21]
Side note: I'm assuming the matrix given to you has 1 row and 4 columns.
Answer:
g
Step-by-step explanation:
The maximum value occurs at gradient 0 (the stationary point).
In f this has a value (y) of 6.
In the equation example we have to differentiate:
dg(x)/dx = -x + 4
Gradient is 0 so 4 - x = 0 so x = 4
Plug g(4)=our maximum=-(1/2)4^2 + 4(4) + 3 = -8 + 16 + 3 = 11
11 > 6 so g has greater maximum.
