All categories

3 years ago

Write the sum as a product of the GCF of 96 + 18?

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

96: 1,2,3,4,6,8,12,16,24,32,48,96

18: 1,2,3,6,9,18

GCF: 6

But, if you're asking what 96 + 18 it's 114

You might be interested in

Let f be the function given by f(x)=3ln⁡(2+x2)cos⁡x. What is the average value of f on the closed interval 2≤x≤6?

ladessa [460]

The average value of f(x) over [2, 6] is given by the definite integral,

$\displaystyle f_{\rm ave[2,6]} = \frac1{6-2} \int_2^6 3\ln(2+x^3)\cos(x) \, dx$

and is approximately -1.67284.

4 0

2 years ago

A triangle with sides 40 feet 50 feet and 60 feet . On a drawing 1 inch equals 10 feet how long are the sides of the triangle on

natulia [17]

40/10=4

50/10=5

60/10=6

the triangle of the drawing has sides of 4 inch 5 inch and 6 inch

5 0

3 years ago

What is the difference between quantity and quality?

kozerog [31]

Quantity is the amount of something you have. Quality is whether the product is good or long-lasting

4 0

3 years ago

Simplify each expression. -10 (n+6)

sertanlavr [38]

Answer:

-10n - 60

Step-by-step explanation:

Use the distributive property to simplify [ a(b + c) = ab + ac ]

-10(n + 6)

(-10 * n) + (-10 * 6)

-10n + -60

-10n - 60

Best of Luck!

4 0

3 years ago

Read 2 more answers

Half-life of Po-210 is 140 days. If the initial mass of the sample is 5

Anna35 [415]

Answer:

$0.625kg$

Step-by-step explanation:

we are given half-life of PO-210 and the initial mass

we want to figure out the remaining mass after 420 days

in order to solve so we can consider the half-life formula given by

$\displaystyle f(t) = a {0.5}^{t/T}$

where:

f(t) is the remaining quantity of a substance after time t has elapsed.
a is the initial quantity of this substance.
T is the half-life

since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5

thus substitute:

$\displaystyle f(420)=5\cdot{0.5}^{420/140}$

reduce fraction:

$\displaystyle f(420)=5\cdot{0.5}^{3}$

By using calculator we acquire:

$\displaystyle f(420)=0.625$

hence, the remaining sample after 420 days is 0.625 kg

4 0

3 years ago