Answer:
C. Triangle BAC is congruent to triangle FDE by AAS
Step-by-step explanation:
BAC names the vertices in the order longest-side, shortest-side. That same order is FDE in the other triangle, eliminating choiced B and D. The triangles are not right triangles, eliminating choice A.
The only viable answer choice is C.
No specific sides are shown as being congruent, but two angles are, so we could claim congruence by ASA or AAS. Answer choice C uses the latter.
Answer:
49
Step-by-step explanation:
Because there is a minus sign infront of x-3, we can convert x-3 into the negative form:
- * x
- * -3
-x + 3
Which gives us:
(-x + 3)(x + 11)
Now expand the brackets with the formula:
(a + b)(c + d) = ac + ad + bc + bd
-x * x = -x²
-x * 11 = -11x
3 * x = 3x
3 * 11 = 33
-x² - 11x + 3x + 33
-x² - 8x + 33
The formula for finding the x coordinate of a vertex in a quadratic equation is:
x = 
Plug known variables in:



Now, to find the y coordinate, plug this variable back into the quadratic equation:
-x² - 8x + 33

y = 49
So the y coordinate of the vertex is 49.
Hope this helps!
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 = 40320.
3/8 because you find the common denominator
8: 8,16,24,32
2: 2,4,6,8
1/2=4/8
7/8-4/8
So the answer is 3/8
You can try to find the denominator and then change the denominator+numerator.
I'm guessing the answer is B? I tried to isolate r and I got that result. Sorry if it's wrong!