Question

A rocket fired two engines simultaneously. One produces a thrust 725 N directly forward while the other gives a 513N thrust at 32.4degrees above the forward direction. Find the magnitude and direction ( relative to the forward direction) of the resultant force that these engines exert on the rocket

Answer 1

Answer:

Magnitude of resultant force is  1190.314 N

Direction of force is 13.352°

Explanation:

given data:

thrust force = 725 N

Angle = 32.4 degree

Let x is consider as positive direction

Resultant force in x direction is  

Rx = 725 + 513cos32.4 = 1158.14 N

and Resultant force perpendicular to x direction is:

Ry = 513sin32.4 = 274.88 N

Magnitude of resultant force is

$R=\sqrt{R_x^2+R_y^2} = 1190.314N$

and resultant force direction is  

$\theta=tan^{-1}\frac{R_y}{R_x} = 13.352\degree$