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hichkok12 [17]
3 years ago
9

You are given two rectangular blocks of shiny metal, Block A and Block B, and are asked to determine which one will float in a b

ath of mercury (a metal that is liquid at room temperature). Block A is 10 cm long, 6 cm wide and 1 cm high and has a mass of 630 g. Block B is 5 cm long, 5 cm wide, 3 cm high, and has a mass of 604 g. If mercury has a density of 13.6 g/cm3, which of the two blocks will float when placed in mercury?
Physics
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

Explanation:

Volume of block A = 10 x 6 x 1 = 60 cm³

Mass of block A = 630 g

density of mass A = mass / density

= 630 / 60 = 10.5g / cm³

Volume of block B = 5 x 5 x 3 = 75 cm³

Mass of block A = 604 g

density of mass A = mass / density

= 604 / 75 = 8.05 g / cm³

Since density of both A and B are less than that of mercury , both will float in mercury.

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Elsa runs 100m. She takes 20s to run this distance. What is Elsa's average speed?
Ne4ueva [31]

Answer:

Average speed = 5 m/s

Explanation:

Given the following data;

Distance = 100m

Time = 20 secs

To find the average speed;

Speed = distance/time

Substituting into the formula, we have;

Speed = 100/20

Speed = 5m/s

Therefore, Elsa's average speed is 5 meters per seconds.

7 0
3 years ago
A 0.58 kg mass is moving horizontally with a speed of 6.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of
Sunny_sXe [5.5K]

Answer:

5.8\; {\rm kg\cdot m \cdot s^{-1}}.

Explanation:

If the mass of an object is m and the velocity of that object is v, the linear momentum of that object would be m\, v.

Assume that the initial velocity of the mass is positive (6.0\; {\rm m\cdot s^{-1}}.) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be (-4.0\; {\rm m\cdot s^{-1}}).

Thus, the change in the velocity of the mass would be:

\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}.

The change in the linear momentum of the mass would be:

\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\  =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}.

Thus, the magnitude of the change of the linear momentum would be 5.8\; {\rm kg \cdot m \cdot s^{-1}}.

7 0
3 years ago
Which of the following quantities are unknown?
Novay_Z [31]

Answer:

unknow e and f

Explanation:

In experiments with alpha particles that are obtained by the method of radioactive decay of atoms, some parameters are known

a) Known. The initial velocity is given by the energy of the particles entities by the atomic nuclei

b) Known. The particle charge always 2e, helium core

c) Known. It is set in the given experiment, in general it is selected as zero

d) Known. Placed by the experimenter

e) Unknown. The speed depends on the interactions with the system

f) Unknown. It depends on the interactions with the system, because the position depends on the interactions

g) Known. It is always the value of a helium nucleo

6 0
4 years ago
At a constant pressure, 10 L of a gas at 546 K is cooled to 273 K
lisabon 2012 [21]

Answer:

5 L

Explanation:

Ideal gas law:

PV = nRT

If P, n, and R are constant, then:

n₁R/P₁ = n₂R/P₂

Using ideal gas law, we can rewrite this as:

V₁/T₁ = V₂/T₂

This is known as Charles' law.

Plugging in values:

10 L / 546 K = V / 273 K

V = 5 L

8 0
4 years ago
Based on your calculations in Activity 3.7B, what are the rates of seafloor spreading for the North Atlantic basin ______cm/yr
Over [174]
It was be at least 67 cm/yr for the North Atlantic
3 0
4 years ago
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