Answer: The balls would hit the ground at the same time.
Explanation: Since there is no air resistance, we would put Galileo's experiment into motion. Galileo once performed an experiment of dropping two items, with different masses, from the tower of Pisa. Since there was no air resistance, the balls hit the ground at the same time. In this problem, the balls are "free-falling." Freefall is a term used in Physics to describe the motion of a falling object experiencing only the acceleration due to gravity. g=9.8 m/s^2 (acceleration due to gravity.) 9.8 will always be the acceleration in a free fall event like this with no air resistance, since Gravity remains constant.
Newton's second law of motion states that F=ma, (force is equal to mass times acceleration), but since Newton also states that f=mg, we can conclude that ma=mg. Stating that no matter what the mass of the object is, both of the objects will fall at the same time with the same velocity.
Answer:
S=
2
1
gt
2
........(1)
And that of the other stone is
S=u(t−n)+
2
1
[g(t−n)
2
]........(2)
Since both the stones meet at the distance so equation (1)and equation(2) will be equal
2
1
gt
2
=u(t−n)+
2
1
[g(t−n)
2
]
gt
2
=2ut−2un+gt
2
+gn
2
−2gnt
t(2gn−2u)=gn
2
−2un
t=
(gn−u)
n(
2
gn
−u)
now putting value of t in equation(1)
s=
2
g
⎣
⎢
⎡
gn−u
2
[n(
2
gn
−u)]
⎦
⎥
⎤
2
S=
2
g
⎣
⎢
⎡
(gn−u)
2
n(
2
gn
−u)
⎦
⎥
⎤
Explanation:
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Answer:
b. Projectiles A & B have the same likelihood of breaking the glass since they have the same initial momentum
.
c. Projectile A has the greater likelihood of breaking the glass since its momentum change is larger.
Explanation:
for option b, the two projectiles have the same initial mass and velocity, hence they posses the same amount of momentum that if sufficient enough could break the glass.
for option c, projectile A changes direction, maintaining the same speed v. Its momentum changes from from mv to -mv, since its speed changed direction.
the difference in momentum becomes
Δp = -mv - mv = -2mv
this is twice the initial momentum.
projectile B changes momentum from mv to 0
Δp = 0 - mv = -mv.
this is half of the final momentum of projectile A.
Also we know that force is proportional to to the rate of change of momentum, which is greater in projectile A, therefore projectile A impacts more force on the glass. Projectile A therefore has the greater likelihood of breaking the glass since its momentum change is larger.
The answer would be B ok man good luck
I hope this helps!
