let's recall that an equilateral triangle has all interior angles of 60°.
Check the picture below.
so as you can see, 2√3 = x = r, namely the radius of the circle.
![\bf \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad \implies A=\pi (2\sqrt{3})^2\implies A=\pi (2^2)(\sqrt{3})^2\implies A=12\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2%5Cqquad%20%5Cqquad%20%5Cimplies%20A%3D%5Cpi%20%282%5Csqrt%7B3%7D%29%5E2%5Cimplies%20A%3D%5Cpi%20%282%5E2%29%28%5Csqrt%7B3%7D%29%5E2%5Cimplies%20A%3D12%5Cpi)
Answer:
Parallel
Step-by-step explanation:
Let the required lines be y-x = 5 and y = x-1
If y-x = 5
y = x + 5
The slope m = 1
For the line y = x - 1
The slope m is also 1
Since the slope of both lines are the same, hence both liens are parallel
1.91 to the nearest tenth is 1.9
Answer:
i think it's 59
Step-by-step explanation:
my bad if u get it wrong or anything
Answer: first option
Step-by-step explanation:
To form an arithmetic sequence, you have that for the sequence
:
![6k-7=22-6k](https://tex.z-dn.net/?f=6k-7%3D22-6k)
Therefore, to calculate the value of k to form an arithmetic sequence, you must solve for k, as following:
- Add like terms:
![6k+6k=22+7\\12k=29](https://tex.z-dn.net/?f=6k%2B6k%3D22%2B7%5C%5C12k%3D29)
- Divide both sides by 12. Then you obtain;
![k=\frac{29}{12}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B29%7D%7B12%7D)