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yanalaym [24]
3 years ago
9

Given: f(x) = x2 and g(x) = 2x +1, find f(g(x)]. 4x² + 4x + 1 4x² + 1 2x²+1

Mathematics
2 answers:
aleksklad [387]3 years ago
8 0

Answer:

\huge\boxed{f\bigg(g(x)\bigg)=4x^2+4x+1}

Step-by-step explanation:

f(x)=x^2;\ g(x)=2x+1\\\\f\bigg(g(x)\bigg)-\text{instead of}\ x\ \text{in}\ f(x)\ \text{put the expression}\ 2x + 1\\\\f\bigg(g(x)\bigg)=f(2x+1)=(2x+1)^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\f\bigg(g(x)\bigg)=(2x)^2+2(2x)(1)+1^2=4x^2+4x+1

kenny6666 [7]3 years ago
3 0

Answer:

4x^2 + 4x + 1 = f(g(x))

Step-by-step explanation:

To create the function f(g(x)), expand (2x + 1)^2:

We get 4x^2 + 4x + 1 = f(g(x))

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3 0
3 years ago
What is the Volume of the square pyramid? (Round to the nearest tenth as needed)
goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}

      b = base length = 25 mm

       H = height

         We have to find 'H' using Pythagorean theorem,

              slant height (hypotenuse) = 28 mm

                                                  leg₁ = base length  ÷ 2 = 25÷2 = 12.5

                                                  leg₂ = H

     H² + (12.5)² = 28²

                  H²   = 784 - 156.25

                         = 627.75

                   \sf H = \sqrt{627.75}

                 H = 25.01 mm

          \sf  \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }

                                                     = 5229 mm³

                                                     

       

\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}

3 0
2 years ago
Read 2 more answers
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