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yanalaym [24]
3 years ago
9

Given: f(x) = x2 and g(x) = 2x +1, find f(g(x)]. 4x² + 4x + 1 4x² + 1 2x²+1

Mathematics
2 answers:
aleksklad [387]3 years ago
8 0

Answer:

\huge\boxed{f\bigg(g(x)\bigg)=4x^2+4x+1}

Step-by-step explanation:

f(x)=x^2;\ g(x)=2x+1\\\\f\bigg(g(x)\bigg)-\text{instead of}\ x\ \text{in}\ f(x)\ \text{put the expression}\ 2x + 1\\\\f\bigg(g(x)\bigg)=f(2x+1)=(2x+1)^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\f\bigg(g(x)\bigg)=(2x)^2+2(2x)(1)+1^2=4x^2+4x+1

kenny6666 [7]3 years ago
3 0

Answer:

4x^2 + 4x + 1 = f(g(x))

Step-by-step explanation:

To create the function f(g(x)), expand (2x + 1)^2:

We get 4x^2 + 4x + 1 = f(g(x))

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2 years ago
What is the absolute change of 12.1 inches to 7.8 inches?
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Answer:

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Step-by-step explanation:

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vitfil [10]

That would be:-

4x - 7 = x + 29

the solution:-

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7 0
3 years ago
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Pls guys help me pls :c​
Vinil7 [7]

Answer: A. x\geq21\dfrac{2}{3} .

Step-by-step explanation:

The given inequation: 81-1\dfrac{1}{5}x\leq55

\Rightarrow\ 81-\dfrac{6}{5}x\leq55

Multiplying 5 on both the sides, we get

5(81-\dfrac{6}{5}x)\leq5\times55\\\\\Rightarrow\ 405-6x\leq275\\\\\Rightarrow\ 6x\geq405-275\\\\\Rightarrow\ 6x\geq130\\\\\Rightarrow\ x\geq\dfrac{130}{6}\\\\\Rightarrow\ x\geq\dfrac{65}{3}\\\\\Rightarrow\ x\geq21\dfrac{2}{3}

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So, the correct option is A. x\geq21\dfrac{2}{3} ..

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