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Alexxx [7]
3 years ago
7

Explain how to solve please

Mathematics
2 answers:
Minchanka [31]3 years ago
7 0
Check the picture below.

surely you know how much that is.

alexandr402 [8]3 years ago
6 0
Find the measure of ED. From the theorem: an angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc.

So, the answer clearly is 4x - 8 = 80/2 (80 is the angle).

To solve it take both fraction to the same denominator.

(8x - 16)/2 = 80/2

Multiply both fractions for 2 to delete denominators.

8x - 16 = 80

Move - 16 to the right of equal with changed sign.

8x = 80 + 16

8x = 96

8x/8 = 96/8

x = 12

Answer C
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What are the x and y-intercepts of the line described by the equation?<br> -6x + 3y = 18.9
-BARSIC- [3]

Answer:

x-intercept - x = 1/2y - 3.15

y-intercept - y = 2x + 6.3

Step-by-step explanation:

For x,

-6x + 3y = 18.9

-6x = -3y + 18.9

x = -3y/-6 + 18.9/-6

x = 1/2y - 3.15

For y,

-6x + 3y = 18.9

3y = 6x + 18.9

y = 6x/3 + 18.9/3

y = 2x + 6.3

8 0
3 years ago
Which equation is the inverse of y = 16x2 + 1?
Llana [10]

Answer:

y=\frac{\sqrt{x-1} }{4}

Step-by-step explanation:

The given equation is

y=16x^2+1

For this function to have an inverse, we must restrict the domain, say x\ge0

We interchange x and y to get,

x=16y^2+1


We now make y the subject to get;


x-1=16y^2


x-1=16y^2

We divide through by 16 to get;


\frac{x-1}{16}=y^2


We now take the square root of both sides to get;

\pm \sqrt{\frac{x-1}{16}}=y


y=\pm \frac{\sqrt{x-1} }{4}


Since  x\ge 0, the inverse function is


y=\frac{\sqrt{x-1} }{4}


6 0
3 years ago
If you knew that the vertical intercept for a straight line was 15, that the slope was -.5, and that the independent variable ha
Finger [1]
Y=-.5x+15 plug in 8 for x and you get 11
7 0
3 years ago
Evaluate-2.75 - f for f = -6.5
Stels [109]

Answer:

Step-by-step explanation:

we have f=-6.5

-2.75- (-6.5)= -2.75+6.5=3.75

4 0
3 years ago
What is this fraction as a decimal?
expeople1 [14]
14.4
hope this helps:)
6 0
3 years ago
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